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BabaBlast [244]
4 years ago
15

How do I solve for b-9-b=-18

Mathematics
1 answer:
OlgaM077 [116]4 years ago
7 0

Answer:

no solutions

Step-by-step explanation:

b-9-b=-18

Combine like terms

0b -9 = -18

-9 = -18

This is never true so there are no solutions

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Help with this word problem???? :)
ycow [4]

Answer:

I'm pretty sure it's 144

Step-by-step explanation:

1.           160 divided by 5 is 32 so 1 quart = 32 pounds

2.          32 times 4.5 = 144

P.S Mark as brainliest rate 5 stars and hit that thanks button!

4 0
3 years ago
Calculate the following and provide your answer as a rational number:
hoa [83]

Answer:

(Can't tell if it's 3/4 plus -7/8 or you need the answer to both so I'll put both of them) 3/4 is .75 -7/8 is -.875. 3/4 + -7/8 is -1/8 which is -.125

5 0
3 years ago
Use the elimination method to solve the system of equations.
omeli [17]

Answer:

A.

Step-by-step explanation:

6 0
3 years ago
A stock priced at $100 has a 70% probability of moving up and a 30% probability of moving down. If it moves up, it increases by
masha68 [24]

Answer:

The probability that after two period we will have the same value of $100 is:

p =0.21+0.21 = 0.42

Step-by-step explanation:

We can analyze this situation by cases.

Stock moves up two times

For this case the final value would be:

$100 *1.02*1.02= $104.04

And the probability associated to this event is 0.7*0.7=0.49

Stock moves down two times

For this case the final value would be:

$100 *(1/1.02)*(1/1.02)= $96.117

And the probability associated to this event is 0.3*0.3=0.09

Stock moves up and then down

For this case the final value would be:

$100 *(1.02)*(1/1.02)= $100

And the probability associated to this event is 0.7*0.3=0.21

Stock moves down and then up

For this case the final value would be:

$100 *(1/1.02)*(1.02)= $100

And the probability associated to this event is 0.3*0.7=0.21

So then the probability that after two period we will have the same value of $100 is :

p =0.21+0.21 = 0.42

7 0
3 years ago
How do you draw the probabilities for this tree diagram?
Likurg_2 [28]

Step-by-step explanation:

The prize is equally likely to have been placed behind doors 1, 2, and 3, so the probabilities of D₁, D₂, and D₃ are equal.

P(D₁) = P(D₂) = P(D₃) = 1/3

The contestant initially chooses door 1, so the host will not open it.

P(H₁|D₁) = P(H₁|D₂) = P(H₁|D₃) = 0

The host will not open the door with the prize.

P(H₂|D₂) = P(H₃|D₃) = 0

The remaining probabilities for each door are equal.

P(H₂|D₁) = P(H₃|D₁) = 1/2

P(H₃|D₂) = 1

P(H₂|D₃) = 1

4 0
3 years ago
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