How do you draw the probabilities for this tree diagram?
1 answer:
Step-by-step explanation:
The prize is equally likely to have been placed behind doors 1, 2, and 3, so the probabilities of D₁, D₂, and D₃ are equal.
P(D₁) = P(D₂) = P(D₃) = 1/3
The contestant initially chooses door 1, so the host will not open it.
P(H₁|D₁) = P(H₁|D₂) = P(H₁|D₃) = 0
The host will not open the door with the prize.
P(H₂|D₂) = P(H₃|D₃) = 0
The remaining probabilities for each door are equal.
P(H₂|D₁) = P(H₃|D₁) = 1/2
P(H₃|D₂) = 1
P(H₂|D₃) = 1
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Answer:
Δ MNO ≅ ΔXYZ by AAS postulate.
Step-by-step explanation:
Given:
,
, and YO = NZ.
Consider YO = NZ
Add OZ on both sides
YO + OZ = NZ + OZ
YZ = NO
Consider triangles Δ MNO and ΔXYZ.
Statement Reason
1. Given
2. Given
3. YZ = NO ∵ YO = NZ
Therefore, the two triangles Δ MNO and ΔXYZ are congruent to each other from AAS postulate as two corresponding angles and a corresponding side are equal to each other.
According to the table, when x = 2, y = 12, and when x = 6, y = 4. We fit them into the slope formula like so:
.
The slope of the line between the two points is -2.