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Amanda [17]
3 years ago
15

Use the elimination method to solve the system of equations.

Mathematics
1 answer:
omeli [17]3 years ago
6 0

Answer:

A.

Step-by-step explanation:

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Find the distance between the points (1,8) and (9, 2).
grin007 [14]

Answer:

distance = \sqrt{(x_{1} -x_{2})^2+(y_{1} -y_{2})^2  }\\\\

             =\sqrt{(9-1)^2+(2-8)^2  }\\\\=\sqrt{8^2 + 6^2}\\\\=\sqrt{64 +36 }\\\\=\sqrt{100} = 10units

6 0
3 years ago
Caleb rides his horse with a constant speed of 20km/h How far can he travel in 1 1/4 hours?​
alexandr402 [8]

Answer:

<h2>25 km</h2>

Step-by-step explanation:

\text{We know:}\\\\v=\dfrac{s}{t}\\\\v-speed\\s-distance\\t-time\\\\\text{We have}\ v=20\ \frac{km}{h}\ \text{and}\ t=1\dfrac{1}{4}h=\dfrac{5}{4}h.\\\\\text{Substitute:}\\\\20=\dfrac{s}{\frac{5}{4}}\\\\20=s\cdot\dfrac{4}{5}\qquad\text{multiply both sides by 5}\\\\100=4s\qquad\text{divide both sides by 4}\\\\25=s\to s=25\ km

6 0
3 years ago
Read 2 more answers
The ground temperature at airport is 12 degrees. The temperature decreases by 5.2 degrees for every mile above ground. What woul
algol13

Answer:

The outside plane located at 3 miles above the airport is of -3.6 degrees.

Step-by-step explanation:

The ground temperature at airport is 12 degrees. The temperature decreases by 5.2 degrees for every mile above ground.

This means that the temperature in n miles above ground is given by:

T(n) = 12 - 5.2n

What would be temperature outside plane located at 3 miles above the airport

This is T(3). So

T(3) = 12 - 5.2*3 = 12 - 15.6 = -3.6

The outside plane located at 3 miles above the airport is of -3.6 degrees.

7 0
3 years ago
Write the equation of the perpendicular bisector of if A(–6, –4) and B(2, 0).
mart [117]

Answer:

(-2 , -2)

Step-by-step explanation:

Here,

(-6,-4)=(x1,y1)

(2,0)=(x2,y2)

Mid point formula,

(x,y)=(x1+x2/2 , y1+y2/2)

=(-6+2/2 , -4+0/2)

=(-2 , -2)

3 0
3 years ago
Can someone please help
Eddi Din [679]

The answer must be No. However, the reasons offered here don't make any sense in relation to the way traffic lights work. I believe the best choice may be

... because the results are likely to occur by chance.

If lights are randomly red or green with equal probability, the probability of encountering 9 of 16 lights in any particular state is about 0.17, high enough to say it could occur by chance.

Lights that are not coordinated are rarely programmed that way, more often being either (a) traffic-controlled, or (b) on a timed cycle that favors one direction over another. That is, their probability of being green is very unlikely to be 1/2 in any sort of random way.

8 0
3 years ago
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