Answer:
The running time is quadratic (O(n²) )
Step-by-step explanation:
For the set up, we have a constant running time of C. The, a log-linearsorting is called, thus, its execution time, denoted by T(n), is O(n*log(n)). Then, we call n times a linear iteration, with a running time of an+b, for certain constants a and b, thus, the running time of the algorithm is
C + T(n) + n*(a*n+b) = an²+bn + T + C
Since T(n) is O(n*log(n)) and n² is asymptotically bigger than n*log(n), then the running time of the algorith is quadratic, therefore, it is O(n²).
Answer:
h = 26
Step-by-step explanation:
45 = h + 19
45-19 = h
26 = h
Answer:
h=−6.28r2+s/6.28r
Step-by-step explanation:
Step 1: Flip the equation.
6.28hr+6.28r2=s
Step 2: Add -6.28r^2 to both sides.
6.28hr+6.28r2+−6.28r2=s+−6.28r2
6.28hr=−6.28r2+s
Step 3: Divide both sides by 6.28r.
6.28hr/6.28r=−6.28r2+s/6.28r
h=−6.28r2+s/6.28r
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Answer:</h2>
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Step-by-step explanation:</h2>
To find the area of an ordinary piece of copier paper I have attached a figure below. As you can see, this ordinary piece of copier paper is a rectangular shape having the following dimensions:
THE FIRST SIDE:
THE SECOND SIDE:
The area of a rectangle can be found as:
