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Gnoma [55]
3 years ago
9

X + 1/2 = 2 which answer choice is correct? A. x = 1.5 B. x = 2/3

Mathematics
2 answers:
8090 [49]3 years ago
7 0

Answer:

1.5

Step-by-step explanation:

1.5 + 1/2 =

1.5  + .5 = 2

kogti [31]3 years ago
6 0

Answer:

B. x = 2/3

Step-by-step explanation:

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I know brainly is not the place to go for math

Step-by-step explanation:

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3 years ago
Quick math question, please help^^
Contact [7]

Answer:

x= 81

Step-by-step explanation:

see attached the solution

4 0
3 years ago
What algebraic expression must be added to the sum of 3x2 +4x+8 and 2x2−6x+3 to give 9x2−2x−5 as the result?
Gnom [1K]

4x² - 16 is the algebraic expression that must be added to get the result as 9x²- 2x - 5.

<u>Step-by-step explanation:</u>

The question is asked for the algebraic expression must be added to the sum of 3x²+4x+8 and 2x2−6x+3 to give 9x²- 2x - 5 as the result.

Therefore,

The first step is to find of sum of 3x²+4x+8 and 2x²-6x+3.

To find the sum :

3x²+4x+8

<u>2x²-6x+3 </u>

<u>5x²-2x+11</u>

The sum is 5x²-2x+11.

Now, the second step is to subtract 5x²-2x+11 from the result 9x²- 2x - 5.

  9x²- 2x - 5

- <u>(5x²-2x+11)</u>

  <u> 4x²    -16 </u>

Thus, 4x²-16 is the algebraic expression that must be added with 5x²-2x+11 to get a result of 9x²- 2x - 5.

3 0
3 years ago
HELP!!!!!!!!!!!
rusak2 [61]
There are 4 people that all I know hope this helps a little
8 0
3 years ago
Read 2 more answers
When a certain prescription drug is taken orally by an adult, the amount of the drug (in mg/L) in the bloodstream at t hours is
castortr0y [4]

Answer:

1. y = f(8)

2. So for t which f'(t) > 0, the drug level in the bloodstream is increasing. And for t which f'(t) < 0, it is decreasing.

Step-by-step explanation:

The concentration of the drug in the bloodstream at t hours is:

y = f(t)

1. What is the concentration of the drug in the bloodstream at t= 8 hours?

At t hours, y = f(t)

So at 8 hours, y = f(8)

2. During what time interval is the drug level in the bloodstream increasing? Decreasing?

A function f(t) is increasing when

f'(t) > 0

And is decreasing when

f'(t) < 0

So for t which f'(t) > 0, the drug level in the bloodstream is increasing. And for t which f'(t) < 0, it is decreasing.

5 0
3 years ago
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