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balandron [24]
3 years ago
7

Si "m" es el lado mayor de un triángulo, dos cuyos ángulos interiores miden 30° y 60°, entonces el perímetro del triángulo es

Mathematics
1 answer:
lions [1.4K]3 years ago
7 0

Answer:

perimetro = \dfrac{(3 + \sqrt{3})m}{2}

Step-by-step explanation:

triángulo 30°-60°-90°

1~:~\sqrt{3}~:~2

1m~:~m\sqrt{3}~:~2m

\dfrac{m}{2}~:~\dfrac{m\sqrt{3}}{2}~:~m

perimetro = \dfrac{m}{2} + \dfrac{m\sqrt{3}}{2} + m

perimetro = \dfrac{m}{2} + \dfrac{m\sqrt{3}}{2} + \dfrac{2m}{2}

perimetro = \dfrac{m + m\sqrt{3} + 2m}{2}

perimetro = \dfrac{3m + m\sqrt{3}}{2}

perimetro = \dfrac{(3 + \sqrt{3})m}{2}

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hope it helps...

have a grat day

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