Answer: D = x'10 − 10x'8 + 40x'6 − 80x'4 + 80x'2 − 32
Step-by-step explanation:
13+3k=11
-Move constant to the right-hand side and change its sign
3k=11-13
Calculate the difference
3k=-2
Divide both sides by 3
K= -2/3
Answer:
3.77min
Step-by-step explanation:
we are given the relationship:
d = Vt + 4.9t²,
where
d = distance in meters = given as 160m
V = launching (aka initial) speed = 24m/min
t = time in min (we are asked to find this)
if we subsititute the above values into the equation:
d = Vt + 4.9t²
160 = 24t + 4.9t²
4.9t² + 24t - 160 = 0 (we simply solve for t)
Using the quadratic formula:
t = { -24 ± √[24² - (4)(4.9)(-160] } / [(2)(4.9)] }
t = 3.77 min or -8.67 min
because time cannot be negative in this case, we pick the positive number.
t = 3.77min
Answer:
(-1 , -4)
Step-by-step explanation:
The left & right is controlled by the "x" in the coordinate (x , y). When you translate to the left 6, it means that you subtract 6.
Subtract 6 from the number in the x-coordinate (5):
(5 (-6), -4)
(-1 , -4)
Your new point is (-1 , -4).
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