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Dvinal [7]
3 years ago
5

Please help I only have a few minutes!!!!!

Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

25 x a real answer and you don ' t

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IF KOBE HAD 8 DUNKS AND LEBRON HAD 10, HOW MANY MORE DUNKS DID LEBRON HAVE THEN KOBE?
pav-90 [236]

Answer:

2

Step-by-step explanation:

10-8

6 0
3 years ago
Read 2 more answers
Brenda sells necklaces at the 23rd Street Flea market. It costs her $10.00 in materials to make the necklaces. She decides to ma
Nuetrik [128]

Answer:

$ 14.00

Step-by-step explanation:

10 · 1.75 = 17.50

17.50 · .20 = 3.5

17.50 - 3.50 = 14.00

good luck, i hope this helps :)

5 0
3 years ago
Graph the relation and its inverse. Use open circles to graph the points of the inverse. x –3 4 6 9 y 5 6 –9 –10
Tema [17]

Answer:

See attached picture.

Step-by-step explanation:

Graph the function as (x,y) points.

(-3,5)

(4,6)

(6,-9)

(9,-10)

These are graphed in black on the picture.

To graph the inverse, switch the points from (x,y) to (y,x).

(5,-3)

(6,4)

(-9,6)

(-10,9)

These are graphed in red on the picture.

4 0
3 years ago
Find the next 2 terms in the Geometric sequence 20,30,45 ...
DochEvi [55]

Answers:

The next two terms are 67.5 and 101.25 in that order.

===========================================

Explanation:

Divide the second term over the first to get 30/20 = 1.5

Divide the third term over the second term to get 45/30 = 1.5

The common ratio is 1.5, which means we multiply 1.5 by each term to get the next term

-------

fourth term = 1.5*(third term) = 1.5*45 = 67.5

fifth term = 1.5*(fourth term) = 1.5*67.5 = 101.25

-------

As a shortcut you can plug n = 4 and n = 5 into the function t(n) = 20*(1.5)^(n-1) to get the fourth and fifth terms respectively.

3 0
3 years ago
Martin's test scores are 84, 72, 94, 83, and 61. What is the range of the test scores?
sammy [17]

Answer:

33.

Step-by-step explanation:

In order to find range, you must subtract the largest amount given by the smallest amount. In this case, it would be 94-61=33.

5 0
3 years ago
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