Answer:
12.5
Step-by-step explanation:
your welcome
n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
-----------------------------------------------------
ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
----------------------------------------------------------
n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
<h3>
Answer: Choice A</h3>
The first line shown in choice A is
which means "the first term is -2"
The next line in choice A means "the nth term (
) is found by multiplying the prior term (
) by 8". Put another way: multiply each term by 8 to get the next term.
first term = -2
second term = 8*(first term) = 8*(-2) = -16
third term = 8*(second term) = 8*(-16) = -128
fourth term = 8*(third term) = 8*(-128) = -1024
and so on.
Answer:
See below in bold.
Step-by-step explanation:
If we add the 2 equations we eliminate x and we get 2y =2.
So y = 1.
Substituting y = 1 in the second equation 1 = x - 3.
So x = 4.
A. One solution: (4, 1).
If we drew a graph we would have 2 lines which intersect at the point (4, 1).
We need to expand the square binomial and then multiply:
<span>3x(x + 3)^2
= 3x(x + 3)</span>(x + 3<span>)
= 3x(x^2 + 6x + 9)
= 3x^3 + 18x^2 + 27x</span>