Find the volumen of the semisphere and subtract the volumes of the two cylinders
1) Volume of the semisphere:
[1/2] (4/3)π(r^3) =[ 2π(1.5m)^3 ]/3 = 7.0686 m^3
2) Volumen of the cylinders:π(r^2)h
a) π(0.75/2m)^2 (1.75m) = 0.7731 m^3
b) π(1/2m)^2 (1.25m) = 0.9818 m^3
3) 7.0686 m^3 - 0.7731 m^3 - 0.9818m^3 = 5.3137 m^3
Answer: 5.3 m^3
Answer:
-$0.90
Step-by-step explanation:
There are only two possible outcomes, winning $23 (W) or losing $15 (L). Therefore:

The probability of the player making his next 3 free throws (P(W)) is:

The probability of the player NOT making his next 3 free throws (P(L)) is:

Expected value (EV) is given by the payoff of each outcome multiplied by its probability:

The expected value of the proposition is -$0.90
Answer:
69 <-- quotient
---
Step-by-step explanation:
8)555
48
--
75
72
--
3 <-- remainder
Answer:
hey
Step-by-step explanation:
Answer:
It comes from correct solution steps and is not a valid solution of the equation.
Step-by-step explanation: