Answer: a=4, b=-8, c=-3
Step-by-step explanation: This equation isn't in standard form. To get it there, subtract -3 from both sides. This gets you an equation of 4x^2-8x-3.
The standard form is ax^2+bx+c.
A is the number before x^2 (4). B is the number before x, and since it's subtracted it's negative (-8). C is the last number, and since it's subtracted it's negative (-3).
We shall use the equation A = i(1 + r/n)^nt
So we shall plug all of that in so it turns out like this:
A = 4000(1 + 0.04/4)^4 x 7
So then that can be simplified to A = (1.01)^28
and then to A = 4000(1.321)
so then A = 5285.16
First do -x then -x to 4x so you have 3x-6=9.
Add 6 to -6 to cancel it out, then add 6 to 9.
3x-6. Divide 3from x, divide 3from 6. X=2. Plz answer my question too plz
-6.
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