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mariarad [96]
3 years ago
7

When a number is decreased by 3%, the result is 80. What is the original number to the nearest tenth?

Mathematics
1 answer:
zzz [600]3 years ago
5 0

Answer:

98

Step-by-step explanation:

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Use the image below to answer the following question. What relationship do the ratios of sin x° and cos y° share? (1 point) A ri
dlinn [17]

Answer:

m 36.606

Step-by-step explanation:

90*sin24

90*0.406

is equal to 36.606

approximately 37

5 0
2 years ago
Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.
natulia [17]

\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k

Divergence is easier to compute:

\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}

\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}

Curl is a bit more tedious. Denote by D_t the differential operator, namely the derivative with respect to the variable t. Then

\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}

\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k

\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k

5 0
4 years ago
Describe the error in finding the median of the data.
damaskus [11]
The error is that the numbers are not in order from least to greatest.
To find the median of data you need to first put the numbers in order from least to greatest.
3 0
3 years ago
Read 2 more answers
A fair coin is flipped four times. What is the probability of getting heads at least once?
Llana [10]
The probability is 15.63%. Solution:
 (1 + 4)! over (1! + 4! + 2 raise to 5)
=5/32
=.1563
=15.63%
6 0
3 years ago
Suppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.6
sergey [27]

Answer:

Below.

= 99.7%

= 100 - 99.7%/2

= 0.3/2

= 0.15%

100% - 0.15%

= 99.85%

5 0
3 years ago
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