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stealth61 [152]
3 years ago
10

When you are multiplying powers, what are you actually doing with the exponents?

Mathematics
2 answers:
givi [52]3 years ago
8 0
If you have (3^4)^3 then you multiply the two exponents to get 3^12. if you have 3^4 x 3^3 then you add the exponents to get 3^7
wlad13 [49]3 years ago
3 0
Adding a zero 10 to the 4th power is 10000 you add how many zeros the power is
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Find the measure of the exterior angle
Studentka2010 [4]
103+53=156
180-156=24
The third angle is 24
So then take 180 because a line is 180 degrees and subtract 24
156 is the final answer
4 0
3 years ago
Read 2 more answers
The altitude a (in feet) of a plane t minutes after liftoff is given by a = 3400t + 600. How many minutes after liftoff is the p
Aloiza [94]

Answer:

6

Step-by-step explanation:

Altitude = 3400t +600

21,000 = 3400t +600

21000-600= 3400t

20400/3400 = 3400t/3400

t= 6

Answered by Gauthmath

4 0
3 years ago
What is the product of 0.42 and 0.03?
ArbitrLikvidat [17]
The product is 0.0126
4 0
3 years ago
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What is the slope of the line through (–4, 3) and (5, 3)?
slamgirl [31]

Answer:

slope = 0

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 4, 3) and (x₂, y₂ ) = (5, 3)

m = \frac{3-3}{5+4} = \frac{0}{9} = 0

8 0
3 years ago
Use the method of cylindrical shells to find the volume v generated by rotating the region bounded by the curves about the given
kondor19780726 [428]

Answer:

The volume is \frac{16\pi}{e}

Step-by-step explanation:

* Lets talk about the shell method

- The shell method is to finding the volume by decomposing

 a solid of revolution into cylindrical shells

- Consider a region in the plane that is divided into thin vertical  

 rectangle

- If each vertical rectangle is revolved about the y-axis, we

 obtain a cylindrical shell, with the top and bottom removed.  

- The resulting volume of the cylindrical shell is the surface area 

  of the cylinder times the thickness of the cylinder

- The formula for the volume will be: V=\int\limits^b_a {2\pi xf(x)} \, dx

  where 2πx · f(x) is the surface area of the cylinder shell and  dx is its

  thickness

* Lets solve the problem

- To find the volume V generated by rotating the region bounded

  by the curves y = 4e^x and y = 4e^-x about the y-axis by use

  cylindrical shells

- Consider that the height of the cylinder is y = (4e^x - 4e^-x)

- Consider that the radius of the cylinder is x

- The limits are x = 0 and x = 1

- Lets take 2π and 4 as a common factor out the integration

∴ V=\int\limits^1_0 {2\pi x(4e^{x}-4e^{-x})} \, dx

∴ V=2\pi(4)\int\limits^1_0 ({xe^{x}-xe^{-x})} \, dx

- To integrate xe^{x} and xe^{-x} we will use

  integration by parts methods \int\ {uv'=uv-\int{v}\,u' }\,

∵ u = x

∴ u' = du/dx = 1 ⇒ differentiation x with respect to x is 1

∵ v' = dv/dx = e^x

- The integration e^x is e^x ÷ differentiation of x (1)

∴ v=\int\ {e^{x}}\, dx= e^{x}

∴ \int\ {xe^{x}} \, dx=xe^{x}-\int\ e^{x}\, dx=xe^{x}-e^{x}

- Similar we will integrate xe^-x

∵ u = x

∴ u' = du/dx = 1

∵ v' = dv/dx = e^-x

- The integration e^-x is e^x ÷ differentiation of -x (-1)

∴ v=\int\ {e^{-x}} \, dx=-e^{-x}

∴ \int\ {x}e^{-x}\, dx=-xe^{-x}+\int\ {e^{-x}} \, dx=-xe^{-x}-e^{-x}

∴ V = 8\pi \int\limits^1_0 ({xe^{x}-xe^{-x})} \, dx=8\pi[xe^{x}-e^{x}+xe^{-x}+e^{-x}] from 0 to 1

- Lets substitute x = 1 minus x = 0

∴ V=8\pi[(1)(e^{1})-(e^{1})+(1)(e^{-1})+(e^{-1})-(0)(e^{0})+(e^{0})-(0)(e^{0})-(e^{0})]

∴ V=8\pi[e^{1}-e^{1}+e^{-1}+e^{-1}-0+1-0-1]=8\pi[2e^{-1}]=16\pi e^{-1}

∵ e^{-1}=\frac{1}{e}

∴ V=\frac{16\pi}{e}

3 0
4 years ago
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