Answer:
C, D and E
Step-by-step explanation:
Assuming
f(x) = √(9−8x)
and the options are:
A. p(x) = √(-8x) and q(x)=9+x
B. p(x) = √(9+x) and q(x)=8x
C. p(x) = √(-x) and q(x)=8x−9
D. p(x)=√(9−x) and q(x)=8x
E. p(x)=√x and q(x)=9−8x
F. p(x)=9−8x and q(x)=√x
G. All of the above
H. None of the above
Substituting in f(x)=p(q(x)) we get:
A. √(-8(9+x)) = √(-72 - 8x)
B. √(9+(8x)) = √(9+8x)
C. √(-(8x−9
)) = √(-8x + 9)
D. √(9−(8x)) = √(9−8x)
E. √(9−8x
)
F. 9−8(√x
) = 9 - 8√x
Answer: x = 4 and y = -3
Step-by-step explanation:
2x + 4y = -4
2x = -4 - 4y
x = -2 - 2y
Now that we have solved the first equation for x, we plug (-2 - 2y) into the other equation in place of x and then solve for y.
3(-2 -2y) + 5y = -3
-6 - 6y + 5y = -3
-y = 3
y = -3
Now that we know y, we plug it into the original equation and solve for x.
2x + 4(-3) = -4
2x + -12 = -4
2x = 8
x = 4
You can check the answer by plugging both x and y into either of the original equations.
X^-2=4. You got it correct:)
1/3^-2
You flip the denominator and the numerator to make the 3^-2 positive.
3^2/1= 3^2= 9
1/2^-3
2^3/1= 2^3= 8
I can already tell you that the negative exponents are not going to be as high in value.
3^-2= 1/3^2= 1/9
2^-3= 1/2^3= 1/8
1/3^-2 (the first option) <=== the highest in value
I hope this helps!
~kaikers
