a line with a slope of 1/8 passes through the point (8, 6). what is its equation in slope intercept form?

In what situations (if any) is Heron’s formula useful for finding the area of a triangle.

Inga [223]

Heron’s formula is useful when we know all three sides of triangle

5 0

2 years ago

The selling price for a classic car is $12,000, which is $500 less than two times its original price. What was the original pric

Rashid [163]

Answer:$6250

Step-by-step explanation:

selling price(sp)=12000

Original price(op)=?

sp+500=2 x op

12000+500=2 x op

12500=2 x op

Divide both sides by 2

12500/2=(2 x op)/2

6250=op

Therefore original price is $6250

6 0

3 years ago

1. The function of lenses is based on the law of refraction. A light beam is traveling from the medium 1 where its speed is V1,

masha68 [24]

Answer:

The index of refraction for Medium 2 would be 1.25

Step-by-step explanation:

We have the following data:

Speed of light in Medium 1 = V₁

Speed of light in Medium 2 = V₂

The speed of Light in Medium 2 is related to speed of light in Medium 1 as:

V₂ = 0.8 V₁

Moreover, it is given that Medium 1 is air with index of refraction equal to 1. i.e.

n₁ = 1

We need to find the index of refraction for medium 2. Lets name it is as n₂.

Snell's law related the above mentioned 4 quantities by following relation:

The ratio of indices of refraction of 2 mediums is equivalent to the reciprocal of ratio of phase velocities in those 2 mediums. Mathematically, this can be written as:

$\frac{n_{1}}{n_{2}} = \frac{V_{2}}{V_{1}}$

Substituting the values we have gives us:

$\frac{1}{n_{2}}=\frac{0.8V_{1}}{V_{1}} \\\\\frac{1}{n_{2}}=0.8\\\\ 1=0.8n_{2}\\\\\frac{1}{0.8}=n_{2}\\\\ n_{2}=1.25$

This means, the index of refraction for Medium 2 would be 1.25

3 0

3 years ago

For any nonzero real number a, the __________ of a is 1/a .

SIZIF [17.4K]

A non zero real number could be written as a/1.

When this gets reversed to be 1/a, it is the multiplicative inverse.

4 0

3 years ago

Read 2 more answers

Please please help!!

shepuryov [24]

Answer:

$\large\boxed{x=0\ and\ x=\pi}$

Step-by-step explanation:

$\tan^2x\sec^2x+2\sec^2x-\tan^2x=2\\\\\text{Use}\ \tan x=\dfrac{\sin x}{\cos x},\ \sec x=\dfrac{1}{\cos x}:\\\\\left(\dfrac{\sin x}{\cos x}\right)^2\left(\dfrac{1}{\cos x}\right)^2+2\left(\dfrac{1}{\cos x}\right)^2-\left(\dfrac{\sin x}{\cos x}\right)^2=2\\\\\left(\dfrac{\sin^2x}{\cos^2x}\right)\left(\dfrac{1}{\cos^2x}\right)+\dfrac{2}{\cos^2x}-\dfrac{\sin^2x}{\cos^2x}=2$

$\dfrac{\sin^2x}{(\cos^2x)^2}+\dfrac{2-\sin^2x}{\cos^2x}=2\\\\\text{Use}\ \sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-(1-\cos^2x)}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-1+\cos^2x}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{1+\cos^2x}{\cos^2x}=2$

$\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{(1+\cos^2x)(\cos^2x)}{(\cos^2x)^2}=2\qquad\text{Use the distributive property}\\\\\dfrac{1-\cos^2x+\cos^2x+\cos^4x}{\cos^4x}=2\\\\\dfrac{1+\cos^4x}{\cos^4x}=2\qquad\text{multiply both sides by}\ \cos^4x\neq0\\\\1+\cos^4x=2\cos^4x\qquad\text{subtract}\ \cos^4x\ \text{from both sides}\\\\1=\cos^4x\iff \cos x=\pm\sqrt1\to\cos x=\pm1\\\\ x=k\pi\ for\ k\in\mathbb{Z}\\\\\text{On the interval}\ 0\leq x$

4 0

3 years ago

a line with a slope of 1/8 passes through the point (8, 6). what is its equation in slope intercept form?​

a line with a slope of 1/8 passes through the point (8, 6). what is its equation in slope intercept form?