The answer to your question is 12b^2
Because 3-12 is -9 pal :)
Answer:
x=63
Step-by-step explanation:
<em>Subtract by 150 from both sides of equation.</em>
<em>150-x-150=87-150</em>
<em>Simplify.</em>
<em>87-150=-63</em>
<em>-x=-63</em>
<em>Divide by -1 from both sides of equation.</em>
<em>-x/1=-63/-1</em>
<em>Simplify, to find the answer.</em>
<em>-63/-1=63</em>
<em>x=63 is the correct answer.</em>
<em>I hope this helps you, and have a wonderful day!</em>
Answer:
18.25
Step-by-step explanation:
Answer:
i hope this works. Feel better soon!
Step-by-step explanation:
1.SAS 2 AAS 3 SAS 4 NOT CONGRUENT 5 SSS 6 ASA
7. ∠BAC≅∠EDC given, BC ≅ CE GIVEN ∠ACB≅∠DCE VERTICAL ANGLES, ΔABC≅ΔDEC AAS
8. ∠PQR≅∠TSR GIVEN R IS MIDPOINT OF PT GIVEN PQ≅ST GIVEN ΔPQR≅ΔTSR HYPOTENUSE LEG THEORUM
9. AC BISECTS BCD GIVEN ∠ABD≅∠ADC GIVEN ∠ACB≅∠ADC BISECTED ANGLES AC≅AC REFLEXIVE PROPERTY OF CONGRUENCE ΔABC≅ΔADC ASA AB≅AC SAME SIDES OF CONGRUENT TRIANGLES
<h2>
Answer with explanation:</h2>
Let 
be the population mean lifetime of circulated $1 bills.
By considering the given information , we have :-
Since the alternative hypotheses is two tailed so the test is a two tailed test.
We assume that the lifetime of circulated $1 bills is normally distributed.
Given : Sample size : n=50 , which is greater than 30 .
It means the sample is large so we use z-test.
Sample mean : 
Standard deviation : 
Test statistic for population mean :-
The p-value= 
Since the p-value (0.0433834) is greater than the significance level (0.02) , so we do not reject the null hypothesis.
Hence, we conclude that we do not have enough evidence to support the alternative hypothesis that the average lifetime of a circulated $1 bill differs from 18 months.
