Area of the word ME = 20 square units
Solution:
Picks' Theorem:
where <em>I </em>is the interior points and <em>B</em> is the points on the boundary.
Let us first find the area of the letter M:
Number of interior points in M = 0
Number of points in the boundary = 22
Using pick's theorem,
Area of M = 
Area of M = 10 square units
Now, find the area of the letter E:
Number of interior points in E = 0
Number of points in the boundary = 22
Using pick's theorem,
Area of E =
Area of E = 10 square units
Area of the word ME = Area of M + Area of E
= 10 square units + 10 square units
Area of the word ME = 20 square units
For the answer to the question above, <span>Well, first let us put up a functional equation. </span>
<span>Since this is an exponential function, it'll be: f(t)=54,000*1.03^t </span>
<span>But we want to know how many wolves there were 10 years ago. </span>
<span>For that, we simply "turn time around", as in: f(t)=54,00*1.03^-t </span>
<span>This displays a decreasing number of wolves, as you turn back time. </span>
<span>Now we simply calculate 54,000*1.03^-10 </span>
<span>which is approximately 40,200?</span>
Answer:
<em> x=15 degrees</em>
Step-by-step explanation:
angle EFC+angle ACF=180(allied angles)
5x + 7x =180
12x =180
<em> x=15 degrees</em>
<em />
<em>Hope you got it </em>
<em>If you have any question just ask me</em>
<em>If you think this is the best answer please mark me as BRAINLIEST</em>
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3.c 153
These are the ones that I could solve
solution: Mr. Schwartz will need to order more wheels after building 12 cars.
explanation:
Mr. Schwartz begins with total number of wheels = 85
he has to order more wheels once he left with less than 40 wheels
so min. no. of wheels he can use before ordering more wheels = 85-40 = 45
Mr. Schwartz uses 4 wheels to build 1 car
Mr. Schwartz uses 45 wheels to build 45÷4 = 11.25 cars
then, if he builds 12 cars then he needs 12×4 = 48 wheels
total supply of wheels he begins with = 85
wheels he used to build 12 cars = 48
so total number of wheels remaining are = 85-48 = 37
since 37 is less than 40 so after building 12 cars Mr. Schwartz need to order more wheels.
