Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.
Let us find z-score of data point 22.03.
Using probability formula 
, we will get:
Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
Answer: (22) $9,075 (23) $656.25 (24) $217.13
<u>Step-by-step explanation:</u>
Cost Function: C(x) = 5.75x + 8,000
C(10,000) = 5.75(10,000) + 8,000
= 57,500 + 8,000
= 65,500
Revenue Function: R(x) = 9.50x
R(7,850) = 9.50(7,850)
= 74,575
Profit Function: P(x) = R(x) - C(x)
= 74,575 - 65,500
= 9,075
*****************************************************************************
Retail = Unit Cost + Unit Cost × Markup
= $375 + $375 × .75
= $375 + $281.25
= $656.25
*****************************************************************************
$225 but if paid within 10 days there is a 3.5% discount
Discount = $225 - $225 × .035
= $225 - $7.88
= $217.13
Answer:
GRAPH D
Step-by-step explanation:
BECASUE IT IS THE WRIGHT ANSWER
Answer:
which part do u need go in and what grade is this work on
