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krok68 [10]
3 years ago
6

What are the solutions to the equation?x² + 3x - 54​

Mathematics
2 answers:
algol133 years ago
7 0

Answer:

x = - 9, x = 6

Step-by-step explanation:

Given

x² + 3x - 54

To find the solutions equate to zero

x² + 3x - 54 = 0 ← in standard form

(x + 9)(x - 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 9 = 0 ⇒ x = - 9

x - 6 = 0 ⇒ x = 6

Radda [10]3 years ago
4 0

Answer:

(x+6)⋅(x−9)

Step by Step

Factoring  x2-3x-54  

The first term is,  x2  its coefficient is  1 .

The middle term is,  -3x  its coefficient is  -3 .

The last term, "the constant", is  -54  

Step-1 : Multiply the coefficient of the first term by the constant   1 • -54 = -54  

Step-2 : Find two factors of  -54  whose sum equals the coefficient of the middle term, which is   -3 .

     -54    +    1    =    -53  

     -27    +    2    =    -25  

     -18    +    3    =    -15  

     -9    +    6    =    -3    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -9  and  6  

                    x2 - 9x + 6x - 54

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (x-9)

             Add up the last 2 terms, pulling out common factors :

                   6 • (x-9)

Step-5 : Add up the four terms of step 4 :

                   (x+6)  •  (x-9)

            Which is the desired factorization

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Answer:

<em>19</em>

Step-by-step explanation:

f(x) =4x^3-8x^2+ax+b has a factor 2x-1 and

when divided by x+2, remainder is 20.

To find:Remainder when divided by (x-1)  ?

Solution:

2x-1 is a factor

2x - 1 = 0 \Rightarrow x = \frac{1}{2} when we put this value of x to the function, it will become 0.

i.e.

\Rightarrow f(\dfrac{1}{2}) =0 =4\times (\dfrac{1}2)^3-8(\dfrac{1}2)^2+\dfrac{a}{2}+b=0\\\Rightarrow \dfrac{1}{2}-2+\dfrac{a}{2}+b=0\\\Rightarrow 1-4+a+2b=0\\\Rightarrow a +2b=3 ......(1)

Remainder is 20 when f(x) is divided by x+2

i.e.

f(-2) =20

\Rightarrow f(-2) =20 =4\times (-2)^3-8(-2)^2-2a+b=20\\\Rightarrow -32-32-2a+b=20\\\Rightarrow -2a+b=84 ...... (2)

Solving (1) and (2), Multiply equation (1) by 2 and adding to (2):

5b=6+84\\\Rightarrow b = \dfrac{90}{5} = \bold{18}

By equation (1):

a+2(18) = 3\\\Rightarrow a = -33

So, the equation becomes:

f(x) =4x^3-8x^2-33x+18

\Rightarrow f(1) = 4(1) -8 (1) -33(1) +18 = \bold{19}

So, when divided by (x-1), remainder will be <em>19</em>.

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