Question

HELP PICTURE SHOWN

Answer 1

Answer: D. $\text{Area of square 1+Area of square 2=Area of square 3 }$

Step-by-step explanation:

Let the 'h' be the length of the hypotenuse of the right angle, 'a' be the side corresponding to the square 2 and 'b' be the side corresponding to the square 1 .

Since, area of square =$(side)^2$

Then, Area of square 1 = $b^2$......................(1)

Area of square 2 = $a^2$......................(2)

Area of square 3 = $h^2$......................(3)

Using Pythagoras theorem in given right triangle, we get

$h^2=a^2+b^2\\\\\Rightarrow\text{Area of square 3 =Area of square 1+Area of square 2 }$ [from (1),(2) and (3)]