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3 years ago

10

Sammy has $140 he’s planning on saving an additional $10 each week write an equation to represent the total amount of money M he

would save after W weeks

1 answer:

mote1985 [20]3 years ago

4 0

140 + 10w = m

10w = $10 per week

140 = what he started with

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caleb wants to rent a kayak. Kayak rental cost 14.50 for a half hour.If caleb rents a kayak for one hour and forty-five minutes.

jolli1 [7]

50.75
you multiply 14.50 times 3.5
the reason why it is 3.5 is because there are two half hours in one hour, and another half hour plus 15 minutes ( which is half of a half hour)
i hope this is clear!!
good luck!!

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3 years ago

The height of a triangle is 9, the length is 5, what is the third side?

pentagon [3]

Use the Pythagorean Theorem to solve for the third side. The third side must be the hypotenuse since the height (vertical leg) is 9, and the length (horizontal leg) is 5.

a² + b² = c², where a and b are the legs and c is the hypotenuse. Plug in 5 and 9 for a and b; solve for c.

5² + 9² = c² ⇒ 25 + 81 = c²

106 = c²

Square root both sides.

c = 10.3

Third side: 10.3

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3 years ago

Here is a list of numbers:<br>-16, -10, 10, -12, -11, -18, -12 ,20 ,-20 ,16<br>State the median.

aleksklad [387]

Answer:

i think -14.5

Step-by-step explanation:

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3 years ago

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The triangles are similar. what is the value of x ?

jonny [76]

$\dfrac{32}{4x+12}=\dfrac{8}{15}\\\\ \dfrac{8}{x+3}=\dfrac{8}{15}\\\\ x+3=15\\\\ x=12$

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3 years ago

Simple random sampling uses a sample of size n from a population of size N to obtain data that can be used to make inferences ab

OLEGan [10]

Answer: 6,77,040 different random samples of four accounts are possible.

Step-by-step explanation:

We have to calculate the different random samples of four accounts are possible from the population of 65 bank accounts.

we are using combination formula for calculating various combination of four accounts:

= $^{n}C_{r}$

Where,

n - total population of bank accounts

r - random samples drawn from the population

= $^{65}C_{4}$

= $\frac{n!}{r!(n-r)!}$

= $\frac{65!}{4!(65-4)!}$

= $\frac{65!}{4!(61)!}$

= 6,77,040 different random samples of four accounts are possible.

5 0

3 years ago