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andrezito [222]
3 years ago
11

When constructing a perpendicular line through a point on a line, how can you verify that the lines constructed are perpendicula

r?
A] Check the angles used in the construction with a straightedge to ensure consistency.

B] Check the distance along the lines at several places with a compass to ensure they are the same length.

C] Check the intersecting lines with the corner of a piece of paper to ensure the lines create 90° angles.

D] Check the distance between the lines at several places with a compass to ensure they are equidistant.
Mathematics
2 answers:
aniked [119]3 years ago
7 0

Answer:

C

Step-by-step explanation:

perpecndicular means they intersect in right angle which is 90°, no matter how long lines are.

Flauer [41]3 years ago
5 0

Answer:

Your correct answer is C] Check the intersecting lines with the corner of a piece of paper to ensure the lines create 90° angles.

No matter how long the lines are if 90 ° is a right angle

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Y=x² + 16x + 64
motikmotik

I'll do the first one to get you started

The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64

Compare that to y = ax^2+bx+c and we see that

a = 1

b = 16

c = 64

Use the values of 'a' and b to get the value of h as shown below

h = -b/(2a)

h = -16/(2*1)

h = -8

This is the x coordinate of the vertex.

Plug this x value into the original equation to find the corresponding y value of the vertex.

y = x^2+16x+64

y = (-8)^2 + 16(-8) + 64

y = 0

Since the y coordinate of the vertex is 0, this means k = 0.

The vertex is (h,k) = (-8, 0)

---------------------

So we found that a = 1, h = -8 and k = 0

Therefore,

f(x) = a(x-h)^2 + k

f(x) = 1(x-(-8))^2 + 0

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is the vertex form

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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
8 0
3 years ago
4. ABCD below is a rectangle. BE=6x+2 and ED=4x+6. Find the length of AC.
Nikolay [14]

Answer:

28 units

Step-by-step explanation:

ABCD is a rectangle. AC and BD are diagonals intersecting at point E.

Diagonals of a rectangle bisect each other.

\therefore BE = ED

\therefore 6x + 2 = 4x + 6

\therefore 6x - 4x= 6-2

\therefore 2x= 4

\therefore x= \frac{4}{2}

\therefore x= 2

\therefore 6x + 2= 6*2+2= 12+2= 14

\therefore BE= 14\: units

\because BD = 2BE

\therefore BD = 2(14)= 28\: units

\because AC = BD (diagonals of a are equal in measure)

\therefore AC = 28\: units

8 0
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