10 xy + 3y + 20 ax + 6a = y(10x+3) + a(20x+6) = y(10x+3)+2a(10x+6)=
(y+2a)(10x+3)
Answer:
Value of ∠ BFG = 135°
Step-by-step explanation:
Given:
AB || CD
∠ AFG = (3x + 15)°
∠ FGD = (5x - 5)°
Find:
∠ BFG
Computation:
We know that;
∠ AFG = ∠ FGD
3x + 15 = 5x - 5
3x - 5x = - 5 - 15
- 2x = - 20
2x = 20
x = 10
Value of ∠ AFG = 3x + 15
Value of ∠ AFG = 3(10) + 15
Value of ∠ AFG = 45°
∠ BFG = 180° - Value of ∠ AFG
∠ BFG = 180° - 45°
∠ BFG = 135°
Value of ∠ BFG = 135°
They're trying to trick you with √2. Remember in the 30/60/90 triangle the sides are in ratio 1:√3:2, with the "1" opposite the 30 degrees.
Here we have
1:√3:2 = 6√2:x:hypotenuse
or
x/(6√2) = √3/ 1
x = 6√2×√3 = 6√6
Answer: AC=6√6
Step-by-step explanation:
please mark me as brainlest
Answer:
Step-by-step explanation:
<u>Given:</u>
- G = (11,-5)
- M = (4,-4)
- R = ?
<u>Solution</u>
<u>As per midpoint formula;</u>
- 4 = (11 + x)/2 ⇒ x + 11 = 8 ⇒ x = 3
- -4 = (-5 + y)/2 ⇒ y - 5 = -8 ⇒ y = -3
- R = (3, -3)