All categories

3 years ago

What are shaped that can classify with these

Mathematics

1 answer:

ella [17]3 years ago

5 0

Answer:A.) triangular prism B.) triangular-based pyramid

Step-by-step explanation:

You might be interested in

Compute the probability of flipping a coin once and getting heads, given that the previous flip was tails.

ra1l [238]

Answer:

the probability to flip a head is 50%

Step-by-step explanation:

I think.

5 0

2 years ago

one hose can fill a goldfish pond in 14 minutes, and the two hoses can fill the same pond in 10 minutes, find how long it takes

likoan [24]

Answer:

Step-by-step explanation:

$\frac{1}{14} +\frac{1}{t} =\frac{1}{10}$

Solving this ^^ would equal t=35.

4 0

3 years ago

Jocelyn walks her dog 5 days each week.Each Walk is 2 1/4 miles long. What is the total number of miles that Jocelyn walks her d

igor_vitrenko [27]

Answer:the answer is c

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

Plz help me with this question

Mila [183]

The correct answer is 1 inch.

4 0

3 years ago

Read 2 more answers