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svetoff [14.1K]
3 years ago
7

-1

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0
WAIT HOLD UP ITS CONFUSING 
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What is 86% written as a fraction in simplest form
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86% written as a fraction is 43/50
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Please help me with this I need the right answer
Grace [21]

Answer:

B is the correct answer.

Step-by-step explanation:

graph attached below, with red as the parent function (f(x)=3^x) and blue as the change (f(x)=3^x-8).

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3 years ago
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Please help
Alekssandra [29.7K]

Answer:

25 in x 15 in

Step-by-step explanation:

Given:

  • Length = 3/5 the width
  • Area = 375 in²

Let width = x

Therefore, length = 3/5 x

First create an equation for the area of the picture based on the given information for its width and length:

\begin{aligned} \implies \textsf{Area of original picture} & = \sf width \times length\\& = x\left(\dfrac{3}{5}x\right)\\& = \dfrac{3}{5}x^2\end{aligned}

We are told the area of the enlarged picture is 375 in².  Therefore, substitute this into the equation and solve for x to find the width of the enlarged picture:

\begin{aligned}\textsf{Area} & = 375\\ \implies \dfrac{3}{5}x^2 & = 375\\ x^2 & =375 \cdot \dfrac{5}{3}\\ x^2 & =625\\ x & = \sqrt{625}\\ x& = 25\end{aligned}

Therefore, the width of the enlarged picture is 25 in.

Substitute the found value of x into the expression for length to find the length of the enlarged picture:

\begin{aligned}\sf Length & = \dfrac{3}{5}x\\\\\implies \sf Length & = \dfrac{3}{5}(25)\\\\& = 15\: \sf in\end{aligned}

Therefore, the dimensions of the enlarged picture are <u>25 in x 15 in</u>.  The width is 25 in and the length is 15 in, as the length is 3/5 of the width.

5 0
2 years ago
The scale of a map is 1:1,000,000. What are the real distances between two points if the distance between them on this map is: 1
snow_lady [41]

Answer:

Step-by-step explanation:

Scale= 1:1,000,000

Scaled distance = 1.8 dm

Actual distance = 1.8*1,000,000 = 1,800,000 dm

3 0
3 years ago
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