Y=x-3 what is my answer
1 answer:
You might be interested in
Not sure if this is very clear
Patty = 45.8%
Bun = 20.8%
Cheese = 8.3%
Sauce = 12.5%
Pickles = 4.2%
Veggies = 8.3%
EXPLANATION :
The equation to find a percentage is part(the broken down calories) over whole ( the total calories) is equal to % which we replace with x (since we’re trying to find the %) over 100 because all percents are out of 100. So for simple terms, p/w = %/100.
What I did was put 550/1200 = x/100, cross multiply, leaving you with 1200x=55000, then divide 55000/1200, giving you 45.8.
Patty = 45.8%
Bun = 20.8%
Cheese = 8.3%
Sauce = 12.5%
Pickles = 4.2%
Veggies = 8.3%
EXPLANATION :
The equation to find a percentage is part(the broken down calories) over whole ( the total calories) is equal to % which we replace with x (since we’re trying to find the %) over 100 because all percents are out of 100. So for simple terms, p/w = %/100.
What I did was put 550/1200 = x/100, cross multiply, leaving you with 1200x=55000, then divide 55000/1200, giving you 45.8.
Answer:
The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 8 - 1 = 7
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.3246
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg
The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg
The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).