Please help any one this is hard for me Thank you

Mathematics

1 answer:

steposvetlana [31]3 years ago

6 0

So the formula I use is S = L + 2B
Surface Area = Lateral Area + 2(Base)
In this case, it would be
Surface Area = Lateral Area + Base, since there is only one base
L= Perimeter(height)
L= 4(3 times 5)
----------------
2
L= 4(15)
------
2
L =60/2
L=30
S= 30 + B
B = 3 times 3 = 9
S= 39

You might be interested in

Kiran and his cousin work during the summer for a landscaping company. Kiran's cousin has been working for the company longer, s

tia_tia [17]

Kiran earns $8.50 per hour.

7 0

3 years ago

0.92 repeating as a fraction<br> (0.9222222222222222222........)

Scrat [10]

Answer:

0.9222222222222222/1

Step-by-step explanation:

8 0

3 years ago

Gina wants to go to the water park with her friends. They have a total of w dollars to buy 5 tickets. Each

geniusboy [140]

Answer:W=5x15

HTH

Step-by-step explanation:

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2

Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$