Solve for d: 2d+1/6=6(1/3d+1)

2 answers:

7 0

2d+1/6=2d+6 (I distributed the 6 to what was in the parentheses)
2d-2d=6-1/6 (I subtracted 2d from both sides to get the variables on one side and 1/6 from both sides to get the variables by themselves)
0=35/6 (combined like terms)
0=35/6 is an untrue statement so x doesn't exist

Colt1911 [192]3 years ago

3 0

2d + 1/6 = 6(1/3d + 1)
2d + 1/6 = 2d + 6
2d - 2d = 6 - 1/6
0d = 35/6

$Ans: \O$

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b) 6.68%

Step-by-step explanation:

Normal Probability Distribution

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In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

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