One hour after a hiker left a camp, a cyclist set out to catch up. If the hiker traveled 3 miles per hour and the cyclist travel
ed 6 miles per hour faster, how long will it take the cyclist to catch up with the hiker?
____hours and ____minutes
2 answers:
Its 23.1 one because in 23 minutes they travel three miles
3mph and 6mph 1hour 30minutes for cyclist to cat
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X=[-(-1)+or-sqrt ((-1)^2-4x1x-2)]/(2x1)
Just subtract 9:00-2:30 so your answer should 6 hours and 30 minutes or 6 1/2 hours
I do not know what point is you trying to find
Answer:f
Step-by-step explanation:
