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Mamont248 [21]
3 years ago
14

One hour after a hiker left a camp, a cyclist set out to catch up. If the hiker traveled 3 miles per hour and the cyclist travel

ed 6 miles per hour faster, how long will it take the cyclist to catch up with the hiker?
____hours and ____minutes
Mathematics
2 answers:
katrin [286]3 years ago
7 0
Its 23.1 one because in 23 minutes they travel three miles

anyanavicka [17]3 years ago
5 0
3mph and 6mph 1hour 30minutes for cyclist to cat
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1. -8(1+4x)+7x=-25-8x <br> 2. -5+6(x-7)=-40+5x<br> Could you show the work?
chubhunter [2.5K]

Answer:

1. x=1

2. x=7

Step-by-step explanation:

1. -8(1+4x)+7x=-25-8x

-8-32x+7x=-25-8x

8x-32x+7x=-25+8

-17x=-25+8

-17x=-17

\frac{-17x}{-17} =\frac{-17}{-17} \\x=1

2. -5+6(x-7)=-40+5x

-5+6x-42=-40+5x

-47+6x=-40+5x

x=47-40

x=7

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2 years ago
Air is being pumped into a spherical balloon at a rate of 5 cm^3/min. Determine the rate at which the radius of the balloon is i
Romashka-Z-Leto [24]

0.08 cm/min

Step-by-step explanation:

Given:

\dfrac{dV}{dt}=5\:\text{cm}^3\text{/min}

Find \frac{dr}{dt} when diameter D = 20 cm.

We know that the volume of a sphere is given by

V = \dfrac{4\pi}{3}r^3

Taking the time derivative of V, we get

\dfrac{dV}{dt} = 4\pi r^2\dfrac{dr}{dt} = 4\pi\left(\dfrac{D}{2}\right)^2\dfrac{dr}{dt} = \pi D^2\dfrac{dr}{dt}

Solving for \frac{dr}{dt}, we get

\dfrac{dr}{dt} = \left(\dfrac{1}{\pi D^2}\right)\dfrac{dV}{dt} = \dfrac{1}{\pi(20\:\text{cm}^2)}(5\:\text{cm}^3\text{/min})

\:\:\:\:\:\:\:= 0.08\:\text{cm/min}

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Answer:

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Step-by-step explanation:

Its correct

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