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Ghella [55]
3 years ago
12

I need help I'm stuck

Mathematics
1 answer:
ankoles [38]3 years ago
8 0
Then put in some butter that will get you out
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(0,5)

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Y intercept is where line touches y axis so x = 0.

(0,5) since it's only 5 and the others don't count.

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Find an equation of the tangent line to the curve,f(x) =1x2+ 1at (0,1) by using the limitdefinition of the derivative. (Dont use
Paraphin [41]

Answer:

y = 1.

Step-by-step explanation:

f(x) = x^2 + 1

We know that:

f'(x) =  \lim_{h \to 0}  \frac{f(x + h) - f(x)}{h}

replacing the function, we get:

f'(x) =  \lim_{h \to 0}  \frac{(x + h)^2 + 1 - (x^2 + 1)}{h} \\       =  \lim_{h \to 0}  \frac{(x + h)^2  - x^2}{h} \\\\       = \lim_{h \to 0}  \frac{x^2 + 2xh + h^2  - x^2}{h} \\\

Now we can simplify this to:

= lim_{h \to 0}  \frac{ 2xh + h^2 }{h}

and solving the quotient, we get:

=  lim_{h \to 0}   2x + h = 2x + 0 = 2x

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The slope of that line will be:

f'(0) = 2*0 = 0

So this is a horizontal line, of the type y = a

And we know that this line must pass through the point (0, 1)

so we must have y = 1.

Then the equation of the tangent line to f(x) at the point (0, 1) is:

y = 1.

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What is p^m divided p^n
skelet666 [1.2K]

P^m-n , 1st option is right answer

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