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4 years ago

3x - 4 < 8 and 2x+ 2 > 4 20 points crq

Mathematics

1 answer:

Gekata [30.6K]4 years ago

4 0

Answer:

x<4 and x>1

Step-by-step explanation:

1) 3x-4<8

Add 4 to both sides first to isolate x.

3x-4<8

+4 +4

3x<12

Divide both sides by 3.

3x<12

/3 /3

x<4

2) 2x+2>4

Subtract both sides by 2 to isolate x.

2x+2>4

-2 -2

2x>2

Divide both sides by 2.

2x>2

/2 /2

x>1

Hope this helped!! Have an amazing day :3

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Step-by-step explanation:

we have

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Part 2) It has the same range as the function $f(x)=-\sqrt{-x}$

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the interval ---> (-∞,0]

Part 3) It has the same domain as the function $f(x)=-\sqrt{x}$

The statement is false

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the interval ---> [0,∞)

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