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1 answer:
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We know that the ocean floor has a depth of 247 ft, and we also know that the diver is<span> underwater at depth of 138 ft, so its distance from the ocean floor will be:
</span>
ft
<span>
Now, the </span>rock formations rises to a peak 171 to above the ocean floor, so to find <span>how many feet below the top of the rock formations is the diver, we are going to subtract the distance to the driver form the ocean floor from the rock formations height:
</span>
ft
<span>
We can conclude that the diver is 62 feet </span><span>below the top of the rock formations.</span>
</span>
<span>
Now, the </span>rock formations rises to a peak 171 to above the ocean floor, so to find <span>how many feet below the top of the rock formations is the diver, we are going to subtract the distance to the driver form the ocean floor from the rock formations height:
</span>
<span>
We can conclude that the diver is 62 feet </span><span>below the top of the rock formations.</span>
Answer:
Step-by-step explanation:
Given
See attachment
Required
The value of x that makes l and m parallel
Let the angles be ABC (See attachment 2)
is corresponding to 50 degrees. So:
is corresponding to 55 degrees. So:
This means that:
Solve for x
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——————————
You have y as an implicit function of x:
sin(xy) – x = 0
Use implicit differentiation. As y is a function of x, then you must apply the chain rule there:
d d
—— [ sin(xy) – x ] = —— (0)
dx dx
d d d
—— [ sin(xy) ] – —— (x) = —— (0)
dx dx dx
d
—— [ sin(xy) ] – 1 = 0
dx
d
—— [ sin(xy) ] = 1
dx
d
cos(xy) · —— (xy) = 1
dx
Now, apply the product rule for that last derivative:
![\mathsf{cos(xy)\cdot \left[\dfrac{d}{dx}(x)\cdot y+x\cdot \dfrac{dy}{dx}\right]=1}\\\\\\ \mathsf{cos(xy)\cdot \left[1\cdot y+x\cdot \dfrac{dy}{dx}\right]=1}\\\\\\ \mathsf{y\,cos(xy)+x\,cos(xy)\cdot \dfrac{dy}{dx}=1}](https://tex.z-dn.net/?f=%5Cmathsf%7Bcos%28xy%29%5Ccdot%20%5Cleft%5B%5Cdfrac%7Bd%7D%7Bdx%7D%28x%29%5Ccdot%20y%2Bx%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdx%7D%5Cright%5D%3D1%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7Bcos%28xy%29%5Ccdot%20%5Cleft%5B1%5Ccdot%20y%2Bx%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdx%7D%5Cright%5D%3D1%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7By%5C%2Ccos%28xy%29%2Bx%5C%2Ccos%28xy%29%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdx%7D%3D1%7D)
dy
Isolate —— :
dx
dy
x cos(xy) · —— = 1 – y cos(xy)
dx
Assuming x cos(xy) ≠ 0,
dy 1 – y cos(xy)
—— = ———————— <——— this is the answer.
dx x cos (xy)
I hope this helps. =)
——————————
You have y as an implicit function of x:
sin(xy) – x = 0
Use implicit differentiation. As y is a function of x, then you must apply the chain rule there:
d d
—— [ sin(xy) – x ] = —— (0)
dx dx
d d d
—— [ sin(xy) ] – —— (x) = —— (0)
dx dx dx
d
—— [ sin(xy) ] – 1 = 0
dx
d
—— [ sin(xy) ] = 1
dx
d
cos(xy) · —— (xy) = 1
dx
Now, apply the product rule for that last derivative:
dy
Isolate —— :
dx
dy
x cos(xy) · —— = 1 – y cos(xy)
dx
Assuming x cos(xy) ≠ 0,
dy 1 – y cos(xy)
—— = ———————— <——— this is the answer.
dx x cos (xy)
I hope this helps. =)