According to the right triangle altitude theorem, AN²=CN*NB=1*NB=NB
ΔANB is a right triangle, so AN²=AB²-NB²=(2√5)²-NB²=20-NB²
NB=20-NB²
solve for NB: NB²+NB-20=0, (NB+5)(NB-4)=0, NB=4 or NB=-5 (ignore this negative root)
AN²=NB=4, so AN=2
AC²=AN²+CN², AC²=2²+1², AC=√5
A. 4 city b 6
B. City a, 8, when rounded 10
City b, 12, when rounded 10
C. City A. 2, 3.5, 4, 4, 5.5, 5..... so it's 4
City B. 3.5, 4, 5, 5.5, 6, 6..... so it's 5.25
Sorry if this all wrong. I'm bad at this kind of stuff lol
Good luck
Step-by-step explanation:
y=(x+5)(x-1)
y=-5 x=0
y=0. x=-5
y=0 x=1
now you got the points so graph will be like
The correct answer is D, y = 7x + 5
Calculate the slope by doing y2 - y1 / x2 - x1
y2 - y1 / x2 - x1
61 -33 / 8 - 4
28 / 4
7
Next find the y intercept by looking at the graph, which is 5 in the case
Put it together and you have y = 7x + 5, or option D
Answer: subtract 5 from both sides
Explanation: get rid of the 5 before moving on to isolating the variable