Answer:
I think you would have to multiply 1,500 by 12 and also by 18 to figure it out.
Step-by-step explanation:
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2015-12-14T20:17:50+00:00If you would like to know what is the value of <span>54 - 4 * a^2 + 3 * b^3 </span>when a = -2 and b = 4, you can calculate this using the following steps:
54 - 4 * a^2 + 3 * b^3 = 54 - 4 * (-2)^2 + 3 * 4^3 = 54 - 4 * 4 + 3 * 64 = 54 - 16 + 192 = 230
If you would like to know what is the value of 54 - 4 * a^2 - 3 * b^3 when a = -2 and b = 4, you can calculate this using the following steps:
54 - 4 * a^2 - 3 * b^3 = <span>54 - 4 * (-2)^2 - 3 * 4^3 = 54 - 4 * 4 - 3 * 64 = 54 - 16 - 192 = -154</span>
Step-by-step explanation:
a). A = {x ∈ R I 5x-8 < 7}
5x - 8 < 7 <=> 5x < 8+7 <=> 5x < 15 =>
x < 3 => A = (-∞ ; 3)
A ∩ N = {0 ; 1 ; 2}
A - N* = (-∞ ; 3) - {1 ; 2}
b). A = { x ∈ R I 7x+2 ≤ 9}
7x+2 ≤ 9 <=> 7x ≤ 7 => x ≤ 1 => x ∈ (-∞ ; 1]
A ∩ N = {0 ; 1}
A-N* = (-∞ ; 1)
c). A = { x ∈ R I I 2x-1 I < 5}
I 2x-1 I < 5 <=> -5 ≤ 2x-1 ≤ 5 <=>
-4 ≤ 2x ≤ 6 <=> -2 ≤ x ≤ 3 => x ∈ [-2 ; 3]
A ∩ N = {0 ; 1 ; 2 ; 3}
A - N* = [-2 ; 3) - {1 ; 2}
d). A = {x ∈ R I I 6-3x I ≤ 9}
I 6-3x I ≤ 9 <=> -9 ≤ 6-3x ≤ 9 <=>
-15 ≤ -3x ≤ 3 <=> -5 ≤ -x ≤ 3 =>
-3 ≤ x ≤ 5 => x ∈ [-3 ; 5]
A ∩ N = {0 ; 1 ; 2 ; 3 ; 4 ; 5}
A - N* = [-3 ; 5) - {1 ; 2 ; 3 ; 4}
The easiest way to determine the answer is to just divide $57/$60 = 0.95 or 95%