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tigry1 [53]
3 years ago
15

Consider the equilibrium reaction below. At high concentrations of HA the solution will be yellow; but at low concentrations of

HA the solution will be red. Initially the equilibrium mixture below is orange (combination of yellow & red). What color is expected after adding some colorless A–(aq) to the equilibrium solution? A-(aq) + H2O(ℓ) ⇋ HA(aq) + OH-(aq)
Chemistry
2 answers:
Travka [436]3 years ago
4 0

Answer:

The correct answer is: Yellow

Explanation:

<u>The given reaction at equilibrium</u>: A⁻(aq) + H₂O(ℓ) ⇋ HA(aq) + OH⁻(aq)

Given: Solution color at high product (HA) concentration = yellow

Solution color at low product (HA) concentration = red

Initial color of solution = orange

According to the Le Châtelier's principle, <u>addition of reactan</u>t to the reaction at equilibrium, shifts the equilibrium towards the right side of the reaction or towards the forward direction. <u>Therefore, favoring the product formation.</u>

So, if the <u>reactant A⁻(aq) is added to the reaction mixture</u>, more product (HA) is produced. <u>Therefore, the concentration of the product HA increases. </u>

Since the solution is <u>yellow in color at high product (HA) concentration</u>.<u> </u>

<u>Therefore, when the concentration of the product HA increases upon the addition of reactant A⁻(aq), the color of the solution changes from orange to yellow.</u>

Ede4ka [16]3 years ago
4 0

Explanation:

Methyl orange is the indicator which shows color transitions from red to orange and from orange to yellow.

This change in color of methyl orange is due to the change occurring in the pH of the solution.

  • When the solution is acidic (pH less than 7) in nature then on addition of methyl orange the color of solution will become red.
  • When solution is neutral (pH = 7) then addition of methyl orange will change the color of solution into orange.
  • When solution is basic (pH more than 7) in nature then addition of methyl orange will change the color of solution into yellow.

Also, according to Le Chatelier's principle any disturbance caused in an equilibrium reaction will tend to shift the equilibrium in a direction away from the disturbance.

So, when A^{-} is added into the solution then it means that we are increasing the amount of reactant.

Therefore, the equilibrium will shift in the forward direction that is, formation of products is favored. As product side contains HA so, this shift in equilibrium will change the color of solution into yellow.

Thus, we can conclude that yellow color is expected after adding some colorless A^{-}(aq) to the equilibrium solution.

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45 moles of H₂ are theoretically needed to produce 30.0 moles of NH₃

<h3>Further explanation</h3>

Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

  • Mole

The mole itself is the number of particles contained in a substance amounting to 6.02.10²³

Mole can also be sought if the amount of substance mass and its molar mass is known

\large{\boxed{\boxed{\bold{mol=\frac{mass}{molar\:mass}}}}

 

Reaction that happens :

N₂ +3H₂ ⇒ 2NH₃

mole N₂ : H₂ : NH₃ = 1 : 3 : 2

To produce 30.0 moles of NH₃,

  • H₂ needed :

mole~H_2~=~\frac{3}{2}\times~30~mole

mole H₂ = 45 mole

  • N₂ needed :

mole~N_2~=~\frac{1}{2}~\times~30

mole N₂ = 15 mole

So the minimum N₂ needed is: 15 mole

14.5 moles of N₂ can only produce NH₃ :

mole~NH_3~=~\frac{2}{1}~\times~14.5

mole NH₃ = 29 mole

<h3>Learn more </h3>

The mass of one mole of raindrops

brainly.com/question/5233234

moles of NaOH

brainly.com/question/4283309

moles of water you can produce

brainly.com/question/1405182

 

Keywords: mole,  NH₃, N₂, H₂

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