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ELEN [110]
3 years ago
10

ANSWER ASAP WILL MARK AS BRAINLEST 99 POINTS

Mathematics
2 answers:
postnew [5]3 years ago
8 0
P(B) = 2/15

The area of rectangle A is 5(7) = 35 in².
The area of rectangle B is 3(4) = 12 in²
The area of square C is 4(4) = 16 in²
The area of rectangle D is 3(9) = 27 in²

The total area of the figure is 35+12+16+27 = 90 in².

The probability of hitting B is 12/90 which simplifies to 2/15.
LUCKY_DIMON [66]3 years ago
4 0
The correct answer is 2/15
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Y – 11 = 3(x – 2) <br> in standard form
emmainna [20.7K]

Answer:

3x + y = -5

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Distributive Property
  • Equality Properties

<u>Algebra I</u>

Standard Form: Ax + By = C

Point-Slope Form: y - y₁ = m(x - x₁)  

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Step-by-step explanation:

<u>Step 1: Define</u>

[PS]   y - 11 = 3(x - 2)

<u>Step 2: Rewrite</u>

<em>Find Standard Form</em>

  1. Distribute 3:                                  y - 11 = 3x - 6
  2. Subtract 3x on both sides:          -3x - y - 11 = -6
  3. Add 11 to both sides:                    -3x - y = 5
  4. Factor -1:                                       -1(3x + y) = 5
  5. Divide -1 on both sides:                3x + y = -5
4 0
3 years ago
It takes Dennis 1 hour to drive 65 miles, 2 hours to drive 130 miles, and 3 hours to drive 195 miles. Write an equation for the
lesya692 [45]

Answer:

y=65x

Step-by-step explanation:

x represents the # of hours

6 0
3 years ago
Read 2 more answers
The area of a circle, in terms of
ch4aika [34]

Answer:

30m

Step-by-step explanation:

A=πr²

225π=πr²

225=r²

r=√225

r=15

d=2r

d=2×15

=30m

3 0
3 years ago
The probabilty that a student owns a car is 0.65 the porbability that a student owns a compuer is 0.82 the probability that a st
DanielleElmas [232]

Question:  The probability that s student owns a car is 0.65, and the probability that a student owns a computer is 0.82.

a. If the probability that a student owns both is 0.55, what is the probability that a randomly selected student owns a car or computer?

b. What is the probability that a randomly selected student does not own a car or computer?

Answer:

(a) 0.92

(b) 0.08

Step-by-step explanation:

(a)

Applying

Pr(A or B) = Pr(A) + Pr(B) – Pr(A and B)................. Equation 1

Where A represent Car, B represent Computer.

From the question,

Pr(A) = 0.65, Pr(B) = 0.82, Pr(A and B) = 0.55

Substitute these values into equation 1

Pr(A or B) = 0.65+0.82-0.55

Pr(A or B) = 1.47-0.55

Pr(A or B) = 0.92.

Hence the probability that a student selected randomly owns a house or a car is 0.92

(b)

Applying

Pr(A or B) = 1 – Pr(not-A and not-B)

Pr(not-A and not-B) = 1-Pr(A or B) ..................... Equation 2

Given: Pr(A or B)  = 0.92

Substitute these value into equation 2

Pr(not-A and not-B) = 1-0.92

Pr(not-A and not-B) = 0.08

Hence the probability that a student selected randomly does not own a car or a computer is 0.08

8 0
2 years ago
BRAINLIEST!!<br> 9. Describe the shape of the data distribution.
Umnica [9.8K]

Answer:

positive skewed

this is correct.

3 0
3 years ago
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