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Zielflug [23.3K]
3 years ago
14

Tell whether the sequence is arithmetic. Justify your answer. If the sequence is arithmetic, write a recursive

Mathematics
1 answer:
navik [9.2K]3 years ago
8 0

Answer:

The explicit formula

a_n = 3 +0.25 (n-1)

The recursive formula

a_1 = 3                            for n=1

a_n = a_ {(n-1)} +0.25     if n>1

Step-by-step explanation:

If a sequence is arithmetical then the difference between any of its consecutive terms will be constant

3, 3.25, 3.5, 3.75,

3.25-3 = 0.25\\\\3.5-3.25 = 0.25\\\\3.75 -3.5 = 0.25

The difference between the consecutive terms remains constant so the sequence is arithmetic.

The explicit formula for an arithmetic sequence is:

a_n = a_1 + d (n-1)

Where d is the constant difference between the terms.

d = 0.25

a_1 is the first term of the sequence.

a_1 = 3

So

a_n = 3 +0.25 (n-1)

Finally, the recursive formula is:

a_1 = 3\\\\a_n = a_ {(n-1)} +0.25

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Answer:

80

Step-by-step explanation:

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Grant has 2 over 3 cup of ice cream in a bowl. He then removes two 1 over 6 cups of ice cream to share with his little brother.
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Todd Holland from NY grows pumpkins. He studied his past records carefully and concluded that his biggest pumpkins are distribut
ehidna [41]

Answer:

P(X>1000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>1000)=P(\frac{X-\mu}{\sigma}>\frac{1000-\mu}{\sigma})=P(Z>\frac{1000-950}{50})=P(z>1)

And we can find this probability using the complement rule and the normal standard table and we got:

P(z>1)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(950,50)  

Where \mu=950 and \sigma=50

We are interested on this probability

P(X>1000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>1000)=P(\frac{X-\mu}{\sigma}>\frac{1000-\mu}{\sigma})=P(Z>\frac{1000-950}{50})=P(z>1)

And we can find this probability using the complement rule and the normal standard table and we got:

P(z>1)=1-P(z

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