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Zielflug [23.3K]
2 years ago
14

Tell whether the sequence is arithmetic. Justify your answer. If the sequence is arithmetic, write a recursive

Mathematics
1 answer:
navik [9.2K]2 years ago
8 0

Answer:

The explicit formula

a_n = 3 +0.25 (n-1)

The recursive formula

a_1 = 3                            for n=1

a_n = a_ {(n-1)} +0.25     if n>1

Step-by-step explanation:

If a sequence is arithmetical then the difference between any of its consecutive terms will be constant

3, 3.25, 3.5, 3.75,

3.25-3 = 0.25\\\\3.5-3.25 = 0.25\\\\3.75 -3.5 = 0.25

The difference between the consecutive terms remains constant so the sequence is arithmetic.

The explicit formula for an arithmetic sequence is:

a_n = a_1 + d (n-1)

Where d is the constant difference between the terms.

d = 0.25

a_1 is the first term of the sequence.

a_1 = 3

So

a_n = 3 +0.25 (n-1)

Finally, the recursive formula is:

a_1 = 3\\\\a_n = a_ {(n-1)} +0.25

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2 years ago
Addition of unlike fractions 5/3 + 7/4​
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Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{3 \frac{5}{12}}}}}}

Step-by-step explanation:

\star{ \sf{ \:  \:  \frac{5}{3}  +  \frac{7}{4}}}

Convert the given fractions into like fractions.

To do so, Take the L.C.M ( Least Common Multiple ) of 3 and 4.

To find out the L.C.M of given numbers,

First of all, find the prime factors of each numbers.

3 = 3 × 1

4 = 2 × 2 × 1

Take out the common prime factor i.e 1

Also take out the other remaining prime factors i.e 2 , 2 and 3

Now, multiply those all prime factors and obtain L.C.M

= 1 × 2 × 2 × 3 = 12

L.C.M of 3 and 4 = 12

\dashrightarrow{ \sf{ \frac{5 \times 4 + 7 \times 3}{12}}}

\dashrightarrow{ \sf{ \frac{20 + 21}{12}}}

Add the numbers : 20 and 21

\dashrightarrow{ \sf{ \frac{41}{12}}}

Convert the improper fraction into mixed fraction

\dashrightarrow{  \boxed{\sf{3 \frac{5}{12} }}}

Remember : While performing the addition or subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fractions. Thus , obtained fractions should be reduced into lowest terms if there are any common on numerator and denominator. But in case of improper fraction, it needs to be deduced on mixed fraction.

Hope I helped!

Best Regards!

~ TheAnimeGirl

4 0
3 years ago
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