Z = -b - a + 1
subtract 1
1z - 1 = -1b - 1a ( 1z is the same as z, same goes for b and a)
add -1b
1b - 1z - 1 = -1a
then we remove -1 by dividing it.
-1b -(-1z) + 1
Answer: -1b -(-1z) + 1 = A
A negative minus a negative is a positive, so the answer might as well be....
-1b + 1z + 1 = A
I'm not sure what the question means by "use S = n^2"...
At any rate, the given sum
1 + 3 + 5 + … + 301
is simply the sum of the first 151 odd positive integers, which we can write in the form 2<em>n</em> - 1 for <em>n</em> between 1 and 151. That is,
We can expand the sum as
Next, recalling that
it follows that
(Probably "S = n^2" means "sum of <em>n</em> odd integers = <em>n</em> ²")
Answer:
5
Step-by-step explanation:
perimiter of rectangle is 3+7+7+3 = 20
square x+x+x+x=20
4x=20
x=20/4
x=5
The denominators stay the same and only the numerator changes.
Answer:
-9.7
Step-by-step explanation:
we can do the opposite of everything that was done to get the resulting difference
so......
-8.4+6.4=-2
-2x19.4=-38.8
-38.8/4=-9.7
and to double check.......
-9.7x4=-38.8
-38.8/19.4=-2
-2-6.4=-8.4