Answer:
12
Step-by-step explanation:
12^2 is the greatest number that is closest to 148. then there is 4 as the smaller number 12-4=8
144+4=148
Answer:
I may not be correct, depending on what you were taught, but it would be...
17/30
Step-by-step explanation:
(2/5×6/6)+(1/6×5/5)
12/30 + 5/30
17/30
keep in mind you don't add the denominators at all ( the numbers at the bottom half of the fraction)
Answer:
We would have

where " l " is length, " w" is width and "h" is height.
Step-by-step explanation:
Step 1
Remember that
Surface area for a box with no top = 
where " l " is length, " w" is width and "h" is height.
Step 2.
Remember as well that
Volume of the box = 
Step 3
We can now use lagrange multipliers. Lets say,

and

By the lagrange multipliers method we know that

Step 4
Remember that

and

So basically you will have the system of equations

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

Then you would get

You can get rid of
from these equations and you would get

And from those equations you would get

Now remember the original equation

If we plug in what we just got, we would have

Answer:
3g+57.50=62.90
Step-by-step explanation:
Your total will be 62.90 so its by its self and you need to subtract 57.50 and divide by 62.90
We are told to use simple interest rate. Formula for this is:

Where:
A= total accumulated amount (principal + interest)
P= principal
r= yearly percentage rate
t= number of years
We need to save $19500 for the first year at a college. This is the amount we will have at the account after five years. In our case this is A.
Principal is the amount we need to put into savings to get the total amount needed. In our case this is P.
Yearly percentage rate is the percentage by which our savings increase at the end of a year. In our case this is r.
t is number of years that we are holding our money on the bank account.
To solve this problem we will assume that we are putting same amount each month on the bank account.
We are given:
A=$19500
P=?
r=1.5%
t=5 years
First step is to transform r into decimal number:

Now we get back to our formula and we solve it for P:

We insert numbers and we get our principal:

We need to put $18139.53 into savings to get required amount after 5 years or 5*12=60months. Assuming that we put same amount each month into savings we need to put

This is our solution for this problem. This is closest to the amount we would need to put in real life. In real life we would earn interest onto interest and our monthly amount would be smaller.