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3 years ago

5/6 divided by 3????? Pls help

Mathematics

2 answers:

Oduvanchick [21]3 years ago

6 0

5/6 divided by 3/1

5/6 *1/3
5/18

pentagon [3]3 years ago

3 0

$\bold{Hey\ there!}$

$\bold{\frac{5}{6}\div3}$

$\bold{Covert:3\ to \rightarrow\frac{3}{1}}$
$\bold{\frac{5}{6}\div\frac{3}{1}}$
$\bold{Cross \ multiply(numerator\times denomenator)}$
$\bold{5\times1=5(\leftarrow numerator)}$
$\bold{6\times3=18(\leftarrow denominator)}$
$\boxed{\boxed{\bold{Your\ answer:\frac{5}{18}}}}\checkmark$

$\bold{Good \ luck\ on \ your \ assignment \ and\ enjoy}$ $\bold{your \ day!}$

~ $\frak{LoveYourselfFirst:)}$

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A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar

ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let $\mu$ = mean waiting time for bus number 14.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 10 minutes {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, $H_A$ : $\mu$ < 10 minutes {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean waiting time = 7.8 minutes

s = sample standard deviation = 2.5 minutes

n = sample of different occasions = 18

So, test statistics = $\frac{7.8-10}{\frac{2.5}{\sqrt{18} } }$ ~ $t_1_7$

= -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0

3 years ago

The seventh grade students are having an end-of-year party in the school cafeteria. There are 754 students attending the party.

valina [46]

Answer:

Determine the number of tables by dividing 754 by 6. If there is a remainder, the answer will need to be rounded tenths or hundredths . There is a remainder, so 125.6 tables are needed.

Step-by-step explanation:

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2 years ago

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Answer: LCM of 8, 12, and 15 is 120.

Step-by-step explanation:

I hope this helps!

6 0

2 years ago

Read 2 more answers

the sum of two numbers is 67 if three times the smaller number is subtracted by the larger the result is 7, find two numbers