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3 years ago

7

Suppose you are making a model where one block represents 5 feet. About how many blocks tall is your model of the Empire State B

uilding? What is the scale factor?

1 answer:

Ymorist [56]3 years ago

3 0

Answer:
250 blocks

Scale factor:

Explanation:
1,250/5=250

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A 2,000-foot-long fence will be used to enclose a rectangular field that is three times as long as it is wide. What is the lengt

BartSMP [9]

I think it's another trick question and the answer is 2000.

4 0

3 years ago

Matthew wants to estimate the mean height of students attending his college. He records the heights of 100 randomly selected stu

Mnenie [13.5K]

The correct option that shows the population of the research carried out by Matthew is;

<u><em>Option D; all the students attending the college</em></u>

<u><em></em></u>

We are told that Matthew wants to estimate the mean height of students attending his college.

Now, let us say the total number of students in his college is x. If he decides to select 100 students randomly to record their height, it means this 100 students is a sample out of the total number of students which is x that is the population.

In conclusion, we can say that the population of this research by Matthew is the total number of students that attend the college.

Read more at; brainly.com/question/6028584

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2 years ago

"a tower is 60 ft tall and 15 ft wide. a model of the tower is 6 in. tall. identify the width of the model in inches.

Lerok [7]

60 ft = 720 inches
15 ft = 180 inches

6 inches / 720 inches = 1/120
x inches / 180 inches = 1/120

1.5 = 1/120 of 180

The width of the model in inches is 1.5 inches.

5 0

3 years ago

Read 2 more answers

What are the first three terms of the sequence represented by the recursive formula

Dimas [21]

Answer: B. 0.25, 3.75, 5.2

Step-by-step explanation:

Since, the given sequence, $a_n= n^2 -a_{n-1}$

And, $a_5=14\frac{1}{4}$

On substituting n=5 in the given recursive formula,

We get, $a_5=5^2-a_{5-1}\implies a_5=25-a_4\implies 14\frac{1}{4}= 25-a_4\implies a_4=10\frac{3}{4}$

For, n=4 $a_4=4^2-a_{4-1}\implies a_4=16-a_3\implies 10\frac{3}{4}= 16-a_3\implies a_3=5\frac{1}{4}\implies a_3=5.25$

For, n=3 $a_3=3^2-a_{3-1}\implies a_3=9-a_2\implies 5.25= 9-a_2\implies a_2=3.75$

For, n=2 $a_2=2^2-a_{2-1}\implies a_2=4-a_1\implies 3.75= 4-a_1\implies a_1=0.25$

Thus, First second and third terms are,

$a_1=0.25$ , $a_2=3.75$ and $a_3=5.25$ .

5 0

2 years ago

Read 2 more answers

ASAP!!! Use the pythagorean theorem to prove that the point (√2/2, √2/2) lies on the unit circle. I need setup, explination, ans

docker41 [41]

Answer:

In brief, apply the pythagorean theorem to show that the distance between the point $(\sqrt{2}/2,\sqrt{2}/2)$ and the origin is $1$ .

Step-by-step explanation:

The pythagorean theorem can give the distance between two points on a plane if their coordinates are known.

A point is on a circle if its distance from the center of the circle is the same as the radius of the circle.

On a cartesian plane, the unit circle is a circle

centered at the origin $(0,0)$
with radius $1$ .

Therefore, to show that the point $(\sqrt{2}/2,\sqrt{2}/2)$ is on the unit circle, show that the distance between $(\sqrt{2}/2,\sqrt{2}/2)$ and $(0,0)$ equals to $1$ .

What's the distance between $(\sqrt{2}/2,\sqrt{2}/2)$ and $(0,0)$ ?

$\displaystyle \sqrt{\left(\frac{\sqrt{2}}{2}-0}\right)^{2} + \left(\frac{\sqrt{2}}{2}-0\right)^{2}} = \sqrt{\frac{1}{2} + \frac{1}{2}}= \sqrt{1}= 1$ .

By the pythagorean theorem, the distance between $(\sqrt{2}/2,\sqrt{2}/2)$ and the center of the unit circle, $(0,0)$ , is the same as the radius of the unit circle, $1$ . As a result, the point $(\sqrt{2}/2,\sqrt{2}/2)$ is on the unit circle.

3 0

3 years ago