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Kruka [31]
3 years ago
7

The following equation has been solved incorrectly. Explain the students error​

Mathematics
2 answers:
balandron [24]3 years ago
6 0
On the right side of the equation, when the student combined like terms, 7x and -4x, they did not combine them correctly. Instead of combining them correctly, the student forgot to include the sign of the -4x which caused the sum of the two terms to be 11x instead of 3x. Hope this helps!
svlad2 [7]3 years ago
3 0
What he said ^^ no problem
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140.132 round to the nearst hundreth
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140.130 is the answer
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2 years ago
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Srekar needs to increase the size of the prism below by 2 inches on each side. The original prism has a length of 3, a depth of
Leto [7]

Answer:

a b

Step-by-step explanation:

The options as obtained from the internet.

- the new prism will have a length of 5

- the new prism will have a depth of 4

- the new prism will have a height of 2

- the volume will increase by 6 and each of the 3 dimensions is increased by 2.

- srekar could increase the volume by the same amount by just adding 6 to the height instead of 2 to each side

The volume of a rectangular prism is (length × depth × height)

Originally, length = 3 inches

Depth = 2 inches

Height = 1 inch

Original volume = 3×2×1 = 6 in³

Then, Sreka adds 2 inches to each of the dimensions,

New length = 3+2 = 5 inches

New depth = 2+2 = 4 inches

New height = 1+2 = 3 inches

New volume = (5×4×3) = 60 in³

Taking each of the statements one at a time

Statement 1

the new prism will have a length of 5

True!

Statement 2

the new prism will have a depth of 4

True!

Statement 3

the new prism will have a height of 2

False! New height = 3 inches

Statement 4

the volume will increase by 6 and each of the 3 dimensions is increased by 2.

This is false. The volume increased to 10 folds of its original volume.

Statement 5

srekar could increase the volume by the same amount by just adding 6 to the height instead of 2 to each side

Adding 6 inches to the height,

New height = 1+6 = 7 inches

New volume = 3×2×7 = 42 in³

This statement is false as the new volume from adding 2 inches to each side is 60 in³

Hope this Helps!!!

5 0
3 years ago
Solve for x (2x-8) (9x-10)
mars1129 [50]

Answer

x+3=17

Step-by-step explanation:

8 0
3 years ago
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Need Help With this question ASAP please help me
Fiesta28 [93]

Answer:

23.5, 23, 13, 12.5

Step-by-step explanation:

3 0
2 years ago
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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
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