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3 years ago

The following equation has been solved incorrectly. Explain the students error

Mathematics

2 answers:

balandron [24]3 years ago

6 0

On the right side of the equation, when the student combined like terms, 7x and -4x, they did not combine them correctly. Instead of combining them correctly, the student forgot to include the sign of the -4x which caused the sum of the two terms to be 11x instead of 3x. Hope this helps!

svlad2 [7]3 years ago

3 0

What he said ^^ no problem

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Help please!

Mamont248 [21]

Answer: see proof below

Step-by-step explanation:

Use the Sum & Difference Identity: cos (A + B) = cos A · cos B - sin A · sin B

Recall the following from Unit Circle: cos (π/2) = 0, sin (π/2) = 1

cos (π) = -1, sin (π) = 0

Use the Quotient Identity: $\tan A=\dfrac{\sin A}{\cos A}$

Proof LHS → RHS:

$\text{LHS:}\qquad \qquad \dfrac{\cos \bigg(\dfrac{\pi}{2}+x\bigg)}{\cos \bigg(\pi +x\bigg)}$

$\text{Sum Difference:}\qquad \dfrac{\cos \dfrac{\pi}{2}\cdot \cos x-\sin \dfrac{\pi}{2}\cdot \sin x}{\cos \pi \cdot \cos x-\sin \pi \cdot \sin x}$

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$=\dfrac{-\sin x}{-\cos x}$

Quotient: tan x

LHS = RHS $\checkmark$

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The following equation has been solved incorrectly. Explain the students error​

The following equation has been solved incorrectly. Explain the students error