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Ludmilka [50]
3 years ago
14

Y = -2x + 3 and y = 3x + 7 How do the slopes and y-intercepts of the two equations compare ?

Mathematics
1 answer:
nignag [31]3 years ago
6 0

Answer:slope = -2 and slope = 3

Y-int 3 and y int = 7

One slope is negative and goes down the other is positive and goes up

Y ints are on the y axis

Step-by-step explanation:

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-2(x-2)=14 what is x?
ryzh [129]
X is equal to 5 because 2x+4=14
7 0
3 years ago
Read 2 more answers
Let $f(x)$ be the real-valued function defined for all real $x$ except for $x = 0$ and $x = 1$ and satisfying the functional equ
Mademuasel [1]
We have to find the values of F.
In this case. F is unlikely to be a polynomial.
But the problem is, we can’t calculate the values of F directly.
There is no real value of x for which x = x−1 x because F isn’t defined at 0 or 1. so,
substituting x = 2.
F(2) + F(1/2) = 3.

Substitute, x = 1/2
F(1/2) + F(−1) = −1/2.
We still are not getting the required value,
therefore,
Substitute x = −1

As, F(2) +F(−1) = 0.
now we have three equations in three unknowns, which we can solve.
It turns out that:
F(2) = 3/4
F(3) = 17/12
F(4) = 47/24
and
F(5) = 99/40

Setting
g(x) = 1 − 1/x
and using
2 → 1/2
to denote
g(2) = 1/2
 we see that :
x → 1 - 1/x → 1/(1-x) →x

so that:
g(g(g(x))) = x.

Therefore, whatever x 6= 0, 1 we start with, we will always get three equations in the three “unknowns” F(x), F(g(x)) and F(g(g(x))).
Now solve these equations to get a formula for F(x)

As,
h(x) = (1+x)/(1−x)
which satisfies h(h(h(h(x)))) = x

Now, mapping x to h(x) corresponds to rotating the circle by ninety degrees.

7 0
3 years ago
Please I need help!!!!!!!!!!!!!!!!!!!!!!!!
Ray Of Light [21]

Answer: 40

Step-by-step explanation:

7 0
2 years ago
Three students were given the expression shown and were asked to take a common factor out of two of the terms. Use the drop-down
Tomtit [17]

Answer:

Calvin: incorrect, sign error

Greg: incorrect, has no relationship to the given expression

Ruben: incorrect, sign error

Equivalent expression: 7 92(4x -11)

Step-by-step explanation:

I hope this helps you :)

<em><u>-KeairaDickson</u></em>

3 0
3 years ago
Find a quadratic polynomial whose sum and and product is -7 and -2
vampirchik [111]

Answer:

<h2>x²+7x-2 = 0</h2>

Step-by-step explanation:

The general form of a quadratic equation with roots a and b is expressed as shown;

x²-(sum of root) x + (product of roots) = 0

x² - (a+b)x + ab = 0 ... 1

Given the sum of roots a+b = -7

Product of roots ab = -2

Substituting this values in equation 1 above wil give;

x²-(-7)x+(-2) = 0

x²+7x-2 = 0

The resulting quadratic polynomial is x²+7x-2 = 0

3 0
2 years ago
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