Your method is completely correct. The first term will be 6 and each subsequent term can be obtained by adding 6 to the previous one, meaning the common difference is 6. The number of terms is given by the highest number that is divisible by 6 and dividing it by 6; that is 996/6 = 166
Then we simply apply the formula for arithmetic sequence sum:
S = n/2 [2a₁ + (n - 1)d]
S = 166/2 [ 2(6) + (166 - 1)6]
S = 83,166
1.-28×-28×-28+13×13×13+16×16×16
=21,952+2,197+4,096
=28,245.
2.12×12×12+-7×-7×-7+-5×-5×-5
=1,728+-343+-125
=1,260
Answer:
(e^3 / e^2n)
Step-by-step explanation:
isn't this the same question
