Answer: Energy is stored in the body primarily as GLYCOGEN in the muscles and liver and as TRIGLYCERIDE in subcutaneous body fat.
Explanation:
We take in food for the purpose of ENERGY, building of worn out tissues of the body and to boost the body immunity. After the intake of food, amino acids from dietary protein are used to synthesize body proteins and other molecules, carbohydrate is used to maintain blood glucose and to build glycogen stores, fat is used for energy or stored in the body.
The body must have a steady supply of energy with some of it coming from the metabolism of glucose.
GLYCOGEN formation occurs when there is excess blood glucose level in the process called glycogenesis. It is the suitable way glucose can be stored as it is insoluble and can not disturb the osmotic pressure of the cells. When food is restricted over time, glycogen stores are expended, and the body must rely on the breakdown of stored GLYCOGEN to be converted to glucose for energy production.
Also, energy for tissues that don't require glucose can come from the breakdown of triglycerides in the adipose tissue. TRIGLYCERIDES are formed by the liver when excess calories are taken, and are stored in the adipose tissues.
Explanation:
WILL GIVE BRAINLIEST! If you can create a data table for the plant growth of a sunflower on a doc for me dated back from oct 6th to today it can be fake just please make it well done
it kinda can be like the pictures below i just need fake heights and fake water measurements but it should add up to 6 inches per week and its for a school project so monday through friday! ill also make a diff question thats worth 100 too
Bacteria reproduce exponentially, and at a brisk pace, meaning one bacterium becomes two, two become four, four become eight, and so on. Because of this, bacteria populations can double in four to twenty minutes, giving bacteria the ability to form millions of cells in as little as a few hours. Under the right conditions, a single bacterial cell can replicate into as many as one billion individual bacteria in just 10 hours.
Answer:
The correct answer is - 1/41,493
Explanation:
Let assume the frequency of the two possible same allele genotype (dominant and recessive) in an inbred population is p and q. Then the frequency of heterozygotes (H) is denoted as:
2pq + 2pqF. ( where F is the inbreeding coefficient).
The frequency of the two different hoozygotes in inbred population can be calculated as:
p2 + pqF and q2 + pqF. (Where p and q are the allele frequency of the dominant and recessive phenotype.
Given: Frequency of Alkaptonuria (q 2) = 1:500, 000
=> q = 1/707
p = 706/707 ( Approx values)
solution:
Inbreeding coefficient (F) = 1/64
Therefore,
Frequency of Alkaptonuria in second cousins= q 2 + pqF
= 1/500, 000 + (706/707 x 1/707) x (1/64)
= 1/500, 000 + 1/45, 248
= 1/41,493 (approx)
