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malfutka [58]
4 years ago
11

What is the solution set for the inequality 3(5- x)<5x-17

Mathematics
2 answers:
Ipatiy [6.2K]4 years ago
5 0

Answer:

The answer is : x>4

Step-by-step explanation:

3(5-x)<5x-17

15-3x<5x-17

-3x-5x<-17-15

-(3x+5x)<-(17+15)

3x+5x>17+15

8x>32

x>\frac{32}{8}

x>4

Nana76 [90]4 years ago
3 0

Answer:

i think the answer is 7

Step-by-step explanation:

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PLEASE ANSWER FAST I WILL GIVE BRAINLIEST
ANTONII [103]

Answer: 10 units²

Step-by-step explanation:

We can divide the shape along the y-axis to get 2 separate triangles. If we find the area of each and add them up, we can get the total area of the figure.

We can get each triangle's area using the formula A = \frac{1}{2}bh

<h3>Left Triangle</h3>

base length - 4 units

height - 4 units

A = \frac{1}{2}(4)(4)

A=\frac{1}{2}(16)

A =8\hspace{0.1cm}units^2

<h3>Right Triangle</h3>

base length - 2 units

height - 2 units

A = \frac{1}{2}(2)(2)

A=\frac{1}{2}(4)

A=2\hspace{0.1cm}units^2

Total = 8 units² + 2 units² = 10 units²

6 0
2 years ago
Which equation represents a line which is parallel to the line 2x+y=-6?
joja [24]
The answer is:  [C]:  " y = -2x - 1 "  .
____________________________________________________
5 0
3 years ago
What are the vertex and x-intercepts of the graph of the function given below?
valentinak56 [21]
Hello : 
x²-2x-24 =( x²-2x+1)-1-24 
              = (x-1)² -25 .....    ( vertex form)
<span>. Vertex: (1, -25);
 intercepts: x = 6, -4 because :
</span>f(x) = 0.....        (x-1)² -25 =0
(x-1)² = 5²
x-1=5 or x-1 = -5
x=6 or x=-4
6 0
3 years ago
Read 2 more answers
66,681 rounded to the nearest ten thousand??
grandymaker [24]

Hey there! I'm happy to help!

This number is sixty six thousand six hundred eighty one. This means that our ten thousandths place is the first 6.

We look to the right place to see if it is 5 or bigger. It is also six.

Therefore we bump the ten thousands place up 1 to 7 and we make everything else 0, giving us 70,000.

Have a wonderful day! :D

7 0
3 years ago
1.) Find the value of the discriminant and the the number of real solutions of
ruslelena [56]
Hi there!

When we have an equation standard form...
a {x}^{2} + bx + c = 0
...the formula of the discriminant is
D = b^2 - 4ac

When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions

1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0

Plug in the values from the equation into the formula of the discriminant

( - 8) {}^{2} - 4 \times 1 \times 7 = 64 - 28 = 36

D > 0 and therefore we have two real solutions.

2.) Find the value of the discriminant and the number of real solutions of
2x^2+4x+2=0

Again, plug in the values from the equation into the formula of the discriminant.

{4}^{2} - 4 \times 2 \times 2 = 16 - 16 = 0

D = 0 and therefore we have one real solution.

~ Hope this helps you.
4 0
3 years ago
Read 2 more answers
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