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3 years ago

11

What is the solution set for the inequality 3(5- x)<5x-17

2 answers:

Ipatiy [6.2K]3 years ago

5 0

Answer:

The answer is : x>4

Step-by-step explanation:

3(5-x)<5x-17

15-3x<5x-17

-3x-5x<-17-15

-(3x+5x)<-(17+15)

3x+5x>17+15

8x>32

x> $\frac{32}{8}$

x>4

Nana76 [90]3 years ago

3 0

Answer:

i think the answer is 7

Step-by-step explanation:

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Natali [406]

When a sphere is cut by a plane which passes through the center, it will create a circle that has the same diameter of the sphere.

To represent this area, you will use the formula for finding area of a circle.

A= pi x r^2
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3 years ago

Write the standard form equation of the ellipse shown in the graph, and identify the foci.

Rama09 [41]

Answer option A

From the given graph is a Vertical ellipse

Center of ellipse = (-2,-3)

Vertices are (-2,3) and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

The distance between center and vertices = 6, so a= 6

The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

$\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2}=1$

(h,k) is the center

we know center is (-2,-3)

h= -2, k = -3 , a= 6 and b = 4

The standard equation becomes

$\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1$

$\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1$

Foci are (h,k+c) and (h,k-c)

$c=\sqrt{a^2-b^2}$

Plug in the a=6 and b=4

$c=\sqrt{6^2-4^2}$

$c=\sqrt{20}$

$c=2\sqrt{5}$ , we know h=-2 and k=-3

Foci are $(-2,-3+2\sqrt{5})$ and $(-2,-3-2\sqrt{5})$

Option A is correct

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3 years ago

Read 2 more answers

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Answer:

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2 years ago

−24= − 3 w + 21 solve for w

loris [4]

Subtract 21 from both sides, it comes to -3, divide -3 by -3 The answer is W=1

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2 years ago

Express the surface area of a cube as a function of its volume v state its domain

Damm [24]

In this question , we have to express the surface area of a cube in terms of volume of the cube .

The formula of volume of cube with edge length s is

$V = s^3$

First we have to solve for s, by taking cube root to both sides. That is

$s = V^{1/3}$

And the formula of surface area of cube is

$S = 6s^2$

Substituting the value of s, we will get

$S= 6(V^{1/3})^2
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THerefore,

$S(V) = 6V^{2/3}$

Domain is related to Volume here.

And Volume cant be negative or 0. So the domain is all positive real numbers .

7 0

3 years ago