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nata0808 [166]
2 years ago
15

Find the least common multiple 18, 9​

Mathematics
2 answers:
Arada [10]2 years ago
8 0

Answer:

The common multiple is 18

Step-by-step explanation:

Because 9*2=18 and 18*1=18

puteri [66]2 years ago
8 0

Answer:

Simply 18.

Step-by-step explanation:

18 = 2*9

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The cost of two books is ₹126.If the cost of one book is twice the other, the find the cost of books.​
Gala2k [10]
$84 is the doubled price and $42
3 0
3 years ago
A thin metal plate, located in the xy-plane, has temperature T(x, y) at the point (x, y). Sketch some level curves (isothermals)
Sophie [7]

Answer:

Step-by-step explanation:

Given that:

T(x,y) = \dfrac{100}{1+x^2+y^2}

This implies that the level curves of a function(f) of two variables relates with the curves with equation f(x,y) = c

here c is the constant.

c = \dfrac{100}{1+x^2+2y^2} \ \ \--- (1)

By cross multiply

c({1+x^2+2y^2}) = 100

1+x^2+2y^2 = \dfrac{100}{c}

x^2+2y^2 = \dfrac{100}{c} - 1 \ \  -- (2)

From (2); let assume that the values of c > 0 likewise c < 100, then the interval can be expressed as 0 < c <100.

Now,

\dfrac{(x)^2}{\dfrac{100}{c}-1 } + \dfrac{(y)^2}{\dfrac{50}{c}-\dfrac{1}{2} }=1

This is the equation for the  family of the eclipses centred at (0,0) is :

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1

a^2 = \dfrac{100}{c} -1  \ \ and \ \ b^2 = \dfrac{50}{c}- \dfrac{1}{2}

Therefore; the level of the curves are all the eclipses with the major axis:

a =  \sqrt{\dfrac{100 }{c}-1}  and a minor axis b =  \sqrt{\dfrac{50 }{c}-\dfrac{1}{2}}  which satisfies the values for which 0< c < 100.

The sketch of the level curves can be see in the attached image below.

7 0
3 years ago
Express as ratio 52 minutes to 2 hours​
just olya [345]

Answer:

52:120

Step-by-step explanation:

1 hour = 60 minutes.

2 hours = 120 minutes.

Answer: 52 : 120

Hope this helps!

8 0
3 years ago
Read 2 more answers
HELP ASAP PLZ!!!!!!!!!!!!!! THANKS IN ADVANCED :)
taurus [48]
I think its the 30x + 20

4 0
3 years ago
The salary of teachers in a particular school district is normally distributed with a mean of $50,000 and a standard deviation o
andrey2020 [161]

Answer:

D. 54,900

Step-by-step explanation:

We have been given that the salary of teachers in a particular school district is normally distributed with a mean of $50,000 and a standard deviation of $2,500.

To solve our given problem, we need to find the sample score using z-score formula and normal distribution table.

First of all, we will find z-score corresponding to probability 0.975(1-0.025) using normal distribution table.  

From normal distribution table, we get z-score corresponding is 1.96.

Now, we will use z-score formula to find sample score as:

z=\frac{x-\mu}{\sigma}, where,

z = Z-score,

z = Sample score,

\mu = Mean,

\sigma = Standard deviation

1.96=\frac{x-50,000}{2,500}

1.96*2,500=\frac{x-50,000}{2,500}*2,500

4900=x-50,000

4900+50,000=x-50,000+50,000

54900=x

Therefore, the salary of $54900 divides the teachers into one group that gets a raise and one that doesn't.

4 0
3 years ago
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