Answer:
x³ + x² − 4x + 6 = 0
Step-by-step explanation:
Imaginary roots come in conjugate pairs. So if 1+i is a root, then 1−i is also a root.
(x − (-3)) (x − (1+i) (x − (1−i)) = 0
(x + 3) (x² − (1+i) x − (1−i) x + (1+i) (1−i)) = 0
(x + 3) (x² − x − ix − x + ix + 1 − i²) = 0
(x + 3) (x² − 2x + 2) = 0
x (x² − 2x + 2) + 3 (x² − 2x + 2) = 0
x³ − 2x² + 2x + 3x² − 6x + 6 = 0
2x^2+4x-30=0
2x^2+10x-6x-30=0
2x(x+5)-6(x+5)=0
(2x-6)(x+5)=0
2x-6=0 x+5=0
x=6/2 x=-5
x=3
(-1,4)
Reflection Rule for over the y axis: A(x,y) A'(-x,y)
Hope this helps!
