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2 years ago

Surely help I’ll brainlist. construct a histogram to represent these results.

Mathematics

1 answer:

AnnZ [28]2 years ago

7 0

Answer:

Step-by-step explanation:

You need to first put the numbers in suitable catagories

0-120

120-130

130-140

140-150

then figure out the frequency of them

0-120=4

121-130=20

131-140=2

141-150=2

then put in a graph(sry its not very good i was in a rush)

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What is the product of (7 x 10^-5) x (5 x 10^-8) (7 x 10^-5) x (5 x 10^-8) = ? x 10^?

arsen [322]

Answer:

$3.5\times10^-^1^2$

Step-by-step explanation:

$(7 \times 10^-5) \times (5 \times 10^-8)$

Evaluate

$(7 \times 5)\times(10^-^5\times10^-^8)$

$35\times10^-^5^-^8$

$35\times10^-^1^3$

$35\times10^1\times10^-^1^3$

$3.5\times10^1^-^1^3$

$3.5\times10^-^1^2$

Thus, the answer is $3.5\times10^-^1^2$

~Lenvy~

7 0

1 year ago

How does f(x) = 3* change over the interval x = 4 to x = 57

Vilka [71]

f(x) increase by a factor of 3

Explanation:

Given that f(x)= 3* and the interval is x=4 to x=57

Now we put the value for x is 4 to 57 then value of f(x) increase with the multiply of 3.

Because the x is multiplied with 3 i.e., 3*

So f(x) increase by a factor of 3.

If we put x=4, then f(x)= 12 (∵ 3×4=12)

If we put x=5, the f(x)= 15 (∵ 3×5=15)

If we put x=6,the f(x)= 18 (∵ 3×6=18)

similarly., values of x= 7,8,9,...155.

Then,

If we put x=56, the f(x)=168

This process will continue until f(x)=171 for x=57.

6 0

3 years ago

a circle is inscribed in a square. the circumference of the circle is increading at a constant rate of 6 inches per second. As t

Burka [1]

Answer:

The rate at which Perimeter of the square is increasing is $\frac{24}{\pi} \ in/secs$ .

Step-by-step explanation:

Given:

Circumference of the circle = $2\pi r$

Rate of change of in circumference = 6 in/secs

We need to find the rate at which the perimeter of the square is increasing

Solution:

Now we know that;

$\frac{d(2\pi r)}{dt} =6\\\\2\pi\frac{dr}{dt}=6\\\\\frac{dr}{dt}=\frac{6}{2\pi}\\\\\frac{dr}{dt}=\frac{3}{\pi}$

Now we know that;

side of the square= diameter of the circle

side of the square = $2r$

Now Perimeter of the square is given by 4 times length of the side.

$P=4\times 2r =8r$

Now we need to find the rate at which Perimeter is increasing so we will find the derivative of perimeter.

$\frac{dP}{dt}= \frac{d(8r)}{dt}\\\\\frac{dP}{dt}= 8\times\frac{dr}{dt}$

But $\frac{dr}{dt} =\frac{3}{\pi}$

So we get;

$\frac{dP}{dt}= 8\times\frac{3}{\pi}\\\\\frac{dP}{dt}= \frac{24}{\pi}\ in/sec$

Hence The rate at which Perimeter of the square is increasing is $\frac{24}{\pi} \ in/secs$ .

5 0

3 years ago

Which equation represents the following situation? The difference of three times a number

Harrizon [31]

The answer is y=-3*x .

3 0

2 years ago

Read 2 more answers

What is the value of x? 64 68 (8x -12) (2x + 18)

tamaranim1 [39]

(8x - 12) + 64 + 68 = 180
(A straight line equals to 180)
8x - 12 + 132 = 180
Combine liked terms
8x + 120 = 180
-120 on both sides
8x = 40
/8 on both sides
x = 5

(8x - 12)
8(5) - 12
40 - 12
28

(2x + 18)
2(5) + 18
10 + 18
28

Answer:
x = 5

4 0

3 years ago