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aliina [53]
2 years ago
8

Pls solve last question pls pls

Mathematics
2 answers:
Alex777 [14]2 years ago
5 0

Answer:

i don't know how to work this

gavmur [86]2 years ago
5 0

Answer:

x = \frac{3}{4} , x = 20

Step-by-step explanation:

2(\frac{3x-5}{x+2} ) - 5 (\frac{x+2}{3x-5} ) = 3

Multiply through by (x + 2)(3x - 5) to eliminate the fractions

2(3x - 5)² - 5(x + 2)² = 3(x + 2)(3x - 5) ← expand factors on both sides

2(9x² - 30x + 25) - 5(x² + 4x + 4) = 3(3x² + x - 10) ← distribute parenthesis

18x² - 60x + 50 - 5x² - 20x - 20 = 9x² + 3x - 30 ← simplify left side

13x² - 80x + 30  = 9x² + 3x - 30 ( subtract 9x² + 3x - 30 from both sides )

4x² - 83x + 60 = 0 factor by splitting the x- term

4x² - 80x - 3x + 60 = 0

4x(x - 20) - 3(x - 20) = 0

(4x - 3)(x - 20) = 0

Equate each factor to zero and solve for x

4x - 3 = 0 ⇒ 4x = 3 ⇒ x = \frac{3}{4}

x - 20 = 0 ⇒ x = 20

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A cylinder and a cone have the same volume. The cylinder has radius x and height y. The cone has radius 2x. Find the height of t
weqwewe [10]
V(cylinder)=πR²H
Radius of the cylinder R=x, height of the cylinder H=y.
We can write for the cylinder
V(cylinder)=πx²y

V(cone) =(1/3)πr²h
Radius of the cone r=2x.
We can write for the cone
V(cone)= (1/3)π(2x)²h=(1/3)π *4*x²h

V(cylinder) =V(cone)
πx²y=(1/3)π *4*x²h
y=(4/3)*h
h=(3/4)*y


7 0
3 years ago
6x-14<-14 or 3x+10>13
kow [346]

Step-by-step explanation:

not sure the question but I can solve the equations

6x-14<-14

6x<0

×<0

3x+10>13

3x>3

×>1

7 0
2 years ago
Answer choices<br> a<br> b<br> c<br> d
Margaret [11]

Answer:

<u><em>Either A or D</em></u>

Step-by-step explanation:

<u><em>I got It right Hope it helps this you guys</em></u>

8 0
3 years ago
write the number 100 as a product of it's prime factor in the same way write the factors in order from smallest to largest
bearhunter [10]

Answer:

Thx for my points back

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
HELP ASAP!!
Tresset [83]

By definition, two angles are supplementary if the sum of them is 180 degrees. In this case (see figure attached with the answer) the line AD is transversal to lines AB and DC. This is a proof of the Same-side interior angle theorem.

This theorem states that if we have two lines that are parallel and we intercept those two lines with a line that is transversal to both, same-side interior angles are formed, and also sum 180º, in other words, they are supplementary angles.

Then:

By the definition of a parallelogram, AB∥DC. AD is a transversal between these sides, so ∠A and ∠D are <em><u>same-side interior angles</u></em>. Because AB and DC are <em><u>parallel</u></em>, the same-side interior angles must be <em><u>supplementary</u></em> by the same-side interior angles theorem. Therefore, ∠A and ∠D are supplementary.


3 0
3 years ago
Read 2 more answers
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